<span>A
and B must be invertible, we have UA=B, since A is invertible. A^-1 exists, by multiplying with A^-1,
we have UA A^-1 =B A^-1. But AA^-1 = I (identity matrix)
and XI=X, for all matrix X, we find UI= B A^-1, and U= B A^-1.</span>
Answer:
Step-by-step explanation:
<u>Given fraction</u>:
Rewrite 9 as 3 · 3:
Cancel the common factor y in the first fraction and the common factor 3 in the second fraction:
Answer:
Ok, so we can express the boys as another letter. just express them as the letter B for boys.
Step-by-step explanation:
I really don't know why.
In one revolution of the wheel, a point on the edge travels a distance equal to the circumference of the wheel.
The wheel has radius 1 ft, so its circumference is 2π (1 ft) = 2π ft.
Then the point has a linear speed of
(1/4 rev/s) * (2π ft/rev) = 2π/4 ft/s = π/2 ft/s
