4 years ago

For which pairs of functions is (f circle g) (x)?

Mathematics

2 answers:

vichka [17]4 years ago

7 0

Pairs are the 2xm6 that’s the answer

Fudgin [204]4 years ago

5 0

Answer:

Its B

f (x) = StartFraction 2 Over x EndFraction and g (x) = StartFraction 2 Over x EndFraction

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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defon

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Step-by-step explanation:

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3 years ago

Read 2 more answers

What are the solutions to 0=x^2-x+1?

kumpel [21]

Answer: No solutions

Step-by-step explanation:

There are no solutions to 0 = x² - x + 1.

[Method One]

We can solve this by rewriting the equation, but it is quicker to graph it when there are no solutions. See attached.

[Method Two]

I said we can solve this by solving an equation, here it is. We will use the quadratic formula since the equation given is already in the proper form.

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$\displaystyle x=\frac{1\pm\sqrt{(-1)^2-4(1)(1)} }{2(1)}$

$\displaystyle x=\frac{1\pm\sqrt{-3} }{2}$

-> Negative numbers don't have real square roots, so there is no solution

4 0

2 years ago