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Novay_Z [31]
3 years ago
7

Jasmine is 60 3/4 inches tall amber is 58 1/4 inches tall. How much taller is jasmine than amber​

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
3 0

Answer:

2½

Step-by-step explanation:

60-58=2

¾-¼

=2/4=½

2+½=2½

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Point b lies on segment AC. find the length of segment BC if AB = 4mm and AC = 4cm
Nataly_w [17]

Answer:

Segment BC = 36 mm or 3.6 cm

Step by Step Explanation:

There are 10 mm in 1 cm

meaning that segment AC is 40 mm long

if AB is 4 mm and it is one part of the two, then we need to subtract that from the total to find out what is left.

40 - 4 = 36

Segment BC = 36 mm or 3.6 cm

4 0
3 years ago
Find the square root of 156.25 by division method
vampirchik [111]
Hello,

I don't know the divison method but is it these one?

156.25= 625/4=(25/2)²

√156.25= 12.5
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3 years ago
I need help with these two fraction questions :(
sammy [17]

Answer:

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Expand the given power using the Binomial Theorem. (10k – m)5
agasfer [191]

Answer:

(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}

∵ The binomial is (10k-m)^{5}

∴ a = 10k , b = -m and n = 5

∴ (10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ (10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})

∴ (10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

5 0
3 years ago
How do you find the AOS and vertex of a quadratic?
andreyandreev [35.5K]

Answer:

The standard form of a quadratic is y = ax^2 + bx + c.

  • In this equation, the formula for the axis of symmetry is x = \frac{-b}{2a}.
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The vertex form of a quadratic is also helpful, y = a(x-h)^2 + k.

  • In this equation, the formula for the center is (h, k), and the axis of symmetry is x = h! That's even easier!
3 0
3 years ago
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