Jasmine is 60 3/4 inches tall amber is 58 1/4 inches tall. How much taller is jasmine than amber

Which of the following equations represents a line that is parallel to the line 3x - 2y = 12

sveticcg [70]

Answer:

Step-by-step explanation:

12=3x-2y

2y+12=3x

2y=3x-12

y=(3x-12)/2

y=mx+b

To be parallel to the line above our line must have the same slope or m. The above line has a slope of 3/2 or 1.5 so the parallel line will be

y=1.5x+b, using point (7,10) we can solve for the y intercept or b

10=1.5(7)+b

10=10.5+b

b=-0.5 so our line is

y=1.5x-0.5

5 0

2 years ago

What dose 5h-2+9h equal explain☺

DerKrebs [107]

Start out by combining LIKE TERMS
5h-2+9h
in this case 9h and 5h are like terms so you would add both of those together.
9h+5h=14h
-2 has no like terms so we can't do anything with it our final answer would be:
14h-2

8 0

3 years ago

Find the least 2-digit whole number N so that the sum 2^9+2^4+N is a perfect square.

oksano4ka [1.4K]

Answer:

N=48

Step-by-step explanation:

2^9+2^4+48=576

576 is a perfect square

3 0

2 years ago

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

6 0

3 years ago

72kg in a ratio of 1:3:5

skad [1K]

first of all you add all of the ratios together so it would be 1+3+5 That equals 9 then divide 72 by 9 which gets you 8. Then you times 8 by all of the ratios to get the answer 8:24:40

4 0

3 years ago

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Jasmine is 60 3/4 inches tall amber is 58 1/4 inches tall. How much taller is jasmine than amber​

Jasmine is 60 3/4 inches tall amber is 58 1/4 inches tall. How much taller is jasmine than amber