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Vera_Pavlovna [14]
3 years ago
14

I NEED HELP ME PLEASE!!

Mathematics
1 answer:
Whitepunk [10]3 years ago
3 0

<u>Answer:</u>

1. The correct answer option is B.

2. The correct answer option is C.

4. The correct answer option is D.

<u>Step-by-step explanation:</u>

1. \frac{3}{x^2+14x+48} ÷ \frac{3}{10x+60}

Changing division to multiplication by taking the reciprocal of the latter fraction:

\frac{3}{x^2+14x+48} \times \frac{10x+60}{3}

\frac{3}{(x+6)(x+8)} \times \frac{10(x+6)}{3}

Cancelling the like terms to get:

\frac{10}{(x+8)}

The correct answer option is B. \frac{10}{(x+8)}

2. \frac{4x^2+36}{4x} \times \frac{1}{5x}

Factorizing the terms and then cancelling the like terms to get:

\frac{4(x^2+9)}{4x} \times \frac{1}{5x}

\frac{x^2+9}{5x^2}

The correct answer option is C. \frac{x^2+9}{5x^2}.

4. \frac{\frac{4t^2-16}{8} }{\frac{t-2}{6} }

Changing division to multiplication by taking the reciprocal of the latter fraction:

\frac{4t^2-16}{8} \times \frac{6}{t-2}

\frac{4(t-2)(t+2)}{8} \times \frac{6}{t-2}

Cancelling the like terms to get:

3(t+2)

The correct answer option is D. 3(t+2).

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Suppose you have 20 coins that total $4.some coins are nickles and sime are quarters .which of the following pairs of equations
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So 1 nickle=5 cents
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n=number of nickles so

total is
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SO THE 2 EQUATIONS WOULD BE
n+q=20
5n+25q=400

so q+n=20
subtract q from both sides
n=20-q
subsitute 20-q for n in the second equation
5(20-q)+25q=400
distribute
100-5q+25q=400
add like terms
100+20q=400
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subsitute 15 for q in first equation

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