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Liono4ka [1.6K]
3 years ago
14

What is the volume of a cylinder with a height of 11.8 cm and a base with a radius of 8.3 cm, to the nearest tenth of a cubic ce

ntimeter?
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

2,553.8 cc

Step-by-step explanation:

Use the volume-of-a-cylinder formula:  V = (base area)(height).

Since the round base of the cylinder has area A = πr², and since r = 8.3 cm and (height) is 11.8 cm, the volume of this cylinder is

V = πr²h = π(8.3 cm)²(11.8 cm) = 2,553.8 cc

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Write the recursive formula for -34, -38, -42, -46, -50 ...
Alex787 [66]

Answer:

-30 - 4n

Step-by-step explanation:

-34, -38, -42, -46, -50 ...

the sequence first term is -34

a= -34

Common difference (d) = T2 - T1 = T3 - T2

d = -38- -34 = -42 -  - 38 = -38+34

d = -4

Formula for nth term

Tn = a + (n-1)d

Tn = -34 + (n -1)-4

Tn = -34 -4n + 4

Tn = -30 - 4n

= -30 - 4n

I hope this was helpful, please mark as brainliest

8 0
4 years ago
Simplify 9y+2y-5y please answer
Brums [2.3K]

Answer:

9y+2y-5y=6y

Step-by-step explanation:

So we have the expression:

9y+2y-5y

To simplify, simply combine the like terms. Therefore:

9y+2y-5y\\=11y-5y\\=6y

Further notes:

To understand why we can combine like terms in the first place, we just need to use the distributive property. So we have the expression:

9y+2y-5y

Now, factor out a y from the three terms:

=y(9+2-5)

Do all the operations inside the parenthesis:

y(9+2-5)\\=y(11-5)\\=y(6)=6y

And we moved the y back to the front!

This is the same result as before. When combining like terms, this is what we're essentially doing but without doing the distributive property manually. I hope you understand a bit better on how and why we can combine like terms!

7 0
3 years ago
Read 2 more answers
What is the answer plsssss help
Sergeu [11.5K]

Answer:

f=9 x 20

Step-by-step explanation:

7 0
3 years ago
URGENT <br>Perform the indicated operation and simplify the result.
yan [13]

Answer:

The answer to your question is:  (2a - 1) / 4

Step-by-step explanation:

         \frac{12a^{2} - 3}{2} (2a + 1)^{-2}  ( \frac{6}{(2a +1)^{-1} } \\

        \frac{3(4a^{2} -1)}{2} \frac{1}{(2z + 1)^{2} } (\frac{2a + 1)}{6}

        \frac{3(2a + 1)(2a- 1) (2a + 1)}{12(2a + 1)(2a + 1)}

        \frac{(2a - 1)}{4}

8 0
3 years ago
The batteries from a certain manufacturer have a mean lifetime of 850 hours, with a standard deviation of 70 hours, assuming tha
matrenka [14]

To answer (a), we will need to find the Z value for 710 hours and 990 hours.

\begin{gathered} For\text{ 710} \\ Z\text{ = }\frac{x-\mu}{\sigma} \\ \text{    = }\frac{710-850}{70} \\ \text{    = -2} \\ p\text{ =0.0228 } \\ For\text{ 990:} \\ Z\text{ = }\frac{990-850}{70} \\ \text{ =2} \\ p\text{ = 0.9772} \end{gathered}\begin{gathered} To\text{ find P \lparen–2 \le Z \le 2\rparen} \\ =\text{ 0.9772 -0.0228} \\ =\text{ 0.9544} \\ =95.44\% \end{gathered}

B) 68% of data lies between one standard deviation of the mean.

850 +70 = 920

850 - 70 = 780

5 0
1 year ago
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