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iVinArrow [24]
4 years ago
6

What problem is http solving?

Computers and Technology
1 answer:
tia_tia [17]4 years ago
4 0

Answer:

umm i need more descriptive details to answer the question buddy

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Starting in 2024 under a new law, all new smartphones sold in the eu must have….
Inga [223]

Answer:

USB type C cables.

Explanation:

3 0
2 years ago
Determine the number of character comparisons made by the brute-force algorithm in searching for the pattern GANDHI in the text
leonid [27]

Answer:

Total number of character comparison = 43

Explanation:

Using the Brute force algorithm

The string of n characters is known as text, and the string of m characters is known as the pattern.

From the given information:

The text (n)=THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED

The pattern (m) = GANDHI

The total no of characters that we have in the text = 47

The total number of characters in pattern = 6

For a brute force algorithm;

Since; the first character of the pattern does not exist in the text, then the number of trials made can be attempted can be expressed as = n – m + 1

= 47 – 6 + 1

= 47 – 5

= 42

Thus; the algorithm will attempt the trial 42 times.

Now, for loop in the algorithm to run 42 times, the G in the pattern will have to align against the for T in the text, and in the last case, it will be aligned against the last space.

On each attempted trial, the algorithm will make one unsuccessful comparison.

However, at the trial at which the G in the pattern Is aligned with the G in the text, there will be two successful comparisons.

Hence, we can calculate the total number of character comparison as follows:

Total number of character comparison = \mathbf{\bigg ( ( 42 -  (no. \ of \  failed \ comparison) ) \times 1 + (1 \times ( Two \ successful \  comparisons) ) \bigg ) }

Total number of character comparison = ( (( 42 – 1) × 1 ) + ( 1 × 2) )

Total number of character comparison = 41 + 2

Total number of character comparison = 43

3 0
3 years ago
The
saveliy_v [14]
The answer is Undo I think
4 0
3 years ago
Read 2 more answers
JAVA
butalik [34]

Answer:

import java.util.*;

public class MyClass {

   public static void main(String args[]) {

       Scanner input = new Scanner(System.in);

       System.out.print("Input a word: ");

       String userinput = input.nextLine();

       for(int i =0;i<userinput.length();i+=2) {

           System.out.print(userinput.charAt(i));

       }

   }

}

Explanation:

This line prompts user for input

       System.out.print("Input a word: ");

This declares a string variable named userinput and also gets input from the user

       String userinput = input.nextLine();

The following iterates through every other character of userinput from the first using iteration variable i and i is incremented by 2

       for(int i =0;i<userinput.length();i+=2) {

This prints characters at i-th position

           System.out.print(userinput.charAt(i));

5 0
3 years ago
Disk ________ realigns separated data so that related file pieces are unified.
PilotLPTM [1.2K]
Disk defragmentation realigns separated data so that related file pieces are unified. <span> Defragmentation is is the process of consolidating fragmented files on the user's hard drive.</span>This Microsoft Windows utility includes <span>rearranging the fragments and restoring them into fewer fragments or into the whole file.
</span>
4 0
3 years ago
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