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astra-53 [7]
3 years ago
9

What’s the correct answer for this?

Mathematics
1 answer:
gulaghasi [49]3 years ago
7 0

Answer:

D.

Step-by-step explanation:

A horizontal translation will move the first triangle a little to the right and then after the vertical translation the triangle will move downwards and will fit into the other triangle thus we will know that the two triangles are congruent.

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bearhunter [10]
17.5 is greater than 1/6
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What is the value of c in the equation y = 4x^2 -10x + c if the y-coordinate of the vertex is -7
love history [14]

Answer: c=-\frac{3}{4}

Step-by-step explanation:

Find the x-coordinate of the vertex with this formula:

x=\frac{-b}{2a}

In this case:

a=4\\b=-10

Substituting values, we get:

x=\frac{-(-10)}{2(4)}=\frac{5}{4}

Now we can substitute the coordinates of the vertex into the equation y = 4x^2 -10x + c and then solve for "c".

Then:

-7 = 4(\frac{5}{4})^2 -10(\frac{5}{4}) + c\\\\-7+\frac{25}{4}=c\\\\c=-\frac{3}{4}

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3 years ago
A woman in a highland village in the Andes knits sweaters and sells them for export. She also takes care of her family and helps
Mnenie [13.5K]

Answer:

Expected number of sweaters per month can be given as follows:

E(X) = Σ x P(X = x)

Now,

E(X) = [2 * 0.1 + 3* 0.1+ 4* 0.2 + 5* 0.3 + 6* 0.2 + 7 * 0.1]

E(X) = 4.7.

Var(X) = E(X^2) – [E(X)]^2

     We have E(X) = 4.7. Thus, [E(X)]2= 4.7*4.7 = 22.09.

Now E(X^2) = [2*2 * 0.1 + 3*3* 0.1+ 4*4* 0.2 + 5*5* 0.3 + 6*6* 0.2 + 7*7*0.1]

    E(X^2) = 24.1

Thus by formula, Var(X) = E(X2) – [E(X)]2

Var(X) = 24.1-22.09

Var(X) = 2.01

Given that exporter pays the $12 for each sweater. The woman pays $2 per sweater. The cost of shipment is $3 irrespective of the number of sweaters. Now, let m is the number of sweaters she made. Thus, the total cost she would have to pay would be

Total cost by woman = 2m+3

The total cost paid by the exporter would be = 12m.

Now the profit of woman would be given by,

                  = The total cost exporter pay – cost paid by the woman

                 = 12m – (2m +3)

                 = 12m – 2m -3

                 = 10m – 3.

Now expected profit made by the woman is given in the following table below:

E(Profit) = Σ profit* P(X = x)

In a similar way, as we have done in part (a).

E(Profit) = [17 * 0.1 + 27* 0.1+ 37* 0.2 + 47* 0.3 + 57* 0.2 + 67 * 0.1]

E(Profit) = 44.

Now, we calculate the variance:

Var(profit) = E(profit^2) – [E(profit)]^2

Var(profit) =

E(profit^2) = [17*17 * 0.1 + 27*27* 0.1+ 37*37* 0.2 + 47*47* 0.3 + 57*57* 0.2 + 67*67*0.1]

    E(profit^2) = 2137.

[E(profit)]^2 = 44*44 = 1936.

Thus, the variance can be given as =

Var(profit)= 2137 – 1936

Var(profit) = 201.

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