Question

(0,-8) and (3,-2) find the distance between each pair of points

Answer 1

Answer:

The distance between the points is 6.71 unit

Explanation:

Given points;

(0,-8) and (3,-2)

The distance between the points is given by;

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

where;

x₁ = 0,    x₂ = 3

y₁ = -8,   y₂ = -2

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\\\d = \sqrt{(3-0)^2 + (-2-(-8))^2} \\\\d = \sqrt{(3^2) \ + (-2+8)^2}\\\\ d = \sqrt{3^2 +6^2 } \\\\d = \sqrt{45} \\\\d = 6.71 \ unit$

Therefore, the distance between the points is 6.71 unit