Factor
in form
ax²+bx+c form
use the ac method
1. mulitply a and c
2. factor the result such that the 2 factors add to b
3. split b into those 2 factors
4. group the terms
5. undistribute common factors
6. undistribute again
first multiply ac
4 times 5=20
now
what 2 numbers multiply to 20 and add to 12
2 and 10
4x²+2x+10x+5
group
(4x²+2x)+(10x+5)
undistribute
2x(2x+1)+5(2x+1)
undistribute the (2x+1)
(2x+1)(2x+5) is factored form whih you have there, nice
Answer:
Question 4: 20 + 6 + 6 + 12 + 16 = 60 
Question 5: 144 + 90 + 90 + 48 + 48 = 420 
Question 6: 78.28 + 78.28 + 88.58 + 27.09 + 27.09 = 299.32 
Step-by-step explanation:
Hope this helps!
Answer:
in graph A the vertex is (0,0)
in graph B the vertex is (0,3)
in graph C the vertex is (0,-3)
And in graph D the vertex is (0,-1)
The axis of symmetry for all of the is 0
And i don't remember maximum and minimum sorry
You need to expand (4x-7)(x+3), multiplying each term in the first bracket by each term in the second bracket, in order to get 4x^2+5x-21. Hope that helps!