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Musya8 [376]
3 years ago
8

mike is filing 2 cylindrical containers with paint. the larger container has dimensions three times those of the smaller contain

er. If there is 0.4 fluid ounce per cubic inch of paint, how many fluid ounces of paint are in the larger container?

Mathematics
1 answer:
ser-zykov [4K]3 years ago
3 0
Bigger is tripples other thing

small radius=5 so big is 5*3=15
small height=6 so big is 6*4=18


Vcylinder=hpir^2
V=18pi15^2
V=18pi225
V=4050pi
pi=3.141592
V=12723.4476 cubic inchs

0.4 per cubic insh

0.4 times 12723.4476=5089.37904 oz



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Pls help me i need help with he answer i been on this question for hours it keeps saying my answer is wrong sooo at this point i
Nikitich [7]

Answer:

-100 + x = 40

Step-by-step explanation:

According to the question:

Tyler's original height = -100 feet

Tyler's final height = 40

X to represent change in elevation

As initial + change = final, the equation would be:  

-100 + x = 40  

Please mark it as brainliest if it helps you!

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5 0
2 years ago
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Solve for y when x = 5.<br> y = 3x + 4
pantera1 [17]

Answer:

19

Step-by-step explanation:

Plug in

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5 0
2 years ago
If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in
Cloud [144]

Answer:

The largest possible volume of the box is 2000000 cubic meters.

Step-by-step explanation:

The volume (V), in cubic centimeters, and surface area (A_{s}), in square centimeters, of the box with a square base are described below:

A_{s} = l^{2}+h\cdot l (1)

V = l^{2}\cdot h (2)

Where:

l - Side length of the base, in centimeters.

h - Height of the box, in centimeters.

By (2), we clear h within the formula:

h = \frac{V}{l^{2}}

And we apply in (1) and simplify the resulting expression:

A_{s} = l^{2}+ \frac{V}{l}

A_{s}\cdot l = l^{3}+V

V = A_{s}\cdot l -l^{3} (3)

Then, we find the first and second derivatives of this expression:

V' = A_{s}-3\cdot l^{2} (4)

V'' = -6\cdot l (5)

If V' = 0 and A_{s} = 30000\,cm^{2}, then we find the critical value of the side length of the base is:

30000-3\cdot l^{2} = 0

3\cdot l^{2} = 30000

l = 100\,cm

Then, we evaluate this result in the expression of the second derivative:

V'' = -600

By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:

V = 30000\cdot l - l^{3}

V = 2000000\,cm^{3}

The largest possible volume of the box is 2000000 cubic meters.

4 0
2 years ago
This one too, again if you dunno it don’t anwser xd
Kobotan [32]

Answer:11

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