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dsp73
3 years ago
12

Jacob wants to make a graph to show the relationship between temperatures in Fahrenheit and degrees Celsius. He plots the follow

ing points:
(11, −11.7), (15, −9.4), (25, −3.9), (35, 1.7), (45, 7.2)

He uses the following steps to plot the graph:


1.Label origin as (0, 0).
2.On x-axis, label Temperature in Fahrenheit.
3. On y-axis, label Temperature in degrees Celsius.
4.The scale on x-axis starts from 0 and goes up to 700 at intervals of 20.
5.The scale on the y-axis starts from −12 and goes up to 12 at intervals of 2.

Which of the following best describes the graph?

It will not be spread out horizontally across the entire coordinate plane because in Step 4, Jacob selected an incorrect scale on the x-axis.

It will not be spread out vertically across the entire coordinate plane because in Step 5, Jacob selected an incorrect scale on the y-axis.

It will not be spread out horizontally across the entire coordinate plane because in Step 2, Jacob plotted Fahrenheit instead of Celsius on the x-axis.

It will not be spread out vertically across the entire coordinate plane because in Step 3, Jacob plotted Celsius instead of Fahrenheit on the y-axis.
Mathematics
1 answer:
____ [38]3 years ago
4 0
Answer: It will not be spread out horizontally across the entire coordinate plane because in Step 2, Jacob plotted Fahrenheit instead of Celsius on the x-axis.

Jacob confused the values, the first coordinate of the ordered pairs (which corresponds to the x-axis) is in Celsius and he used it as Farenheit.

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ax² + bx + c = 0

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First, rewrite the first equation so that the first coefficient is 1. Divide everything by a.

(ax² + bx + c = 0)/a =

x² + (b/a)x + (c/a) = 0

Isolate (c/a) by subtracting (c/a) from both sides

x² + (b/a)x + (c/a) (-(c/a) = 0 (- (c/a)

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Add spaces

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Take 1/2 of the middle term's coefficient and square it. Remember that what you add to one side, you add to the other.

x² + (b/a)x + (b/2a)² = -c/a + (b/2a)²

Simplify the left side of the equation.

x² + (b/a)x + (b/2a)² = (x + (b/2a))²

(x + b/2a))² = ((b²/4a²) - (4ac/4a²)) -> ((b² - 4ac)/(4a²))

Take the square root of both sides of the equation

√(x + b/2a))² = √((b²/4a²) - (4ac/4a²))

x + b/(2a) = (±√(b² - 4ac)/2a

Simplify. Isolate the x.

x = -(b/2a) ± (∛b² - 4ac)/2a = (-b ± √(b² - 4ac))/2a

~

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3 years ago
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