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3 years ago

What is 3v+7v+9v equal to

Mathematics

1 answer:

Fofino [41]3 years ago

5 0

Answer:

19v

Step-by-step explanation:

3v, 7v, and 9v all have the same variable, therefor, you can add all of them up as you would regular numbers, you just have to add "v" at the end.

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Answer fasttt plsssssss

Vlad [161]

Answer:

25ax25b= 625

5 0

2 years ago

a student measured the temperature in degrees celsius for several winter days and recorded the data in a list find the average o

NemiM [27]

Answer:

Average = -1°C

Step-by-step explanation:

The data recorded is;

6, -7, -5, 5, -8, 3 (in °C)

Average = $\frac{6 - 7 - 5 + 5 - 8 + 3}{6}$ = -1°C

8 0

3 years ago

Read 2 more answers

Please help write the equation of the line.

AfilCa [17]

Answer:

x -2y -2=0

Step-by-step explanation:

using the formula, m= ( Y2 - Y1)/( X2-X1)

the gradient is found. the coordinates chosen are (2,0) and ( 0,-1)

the equation of the line is obtained using the formula

y -y1= m(x -x1)

3 0

2 years ago

Dave is comparing the circumferences of several trees in his yard. The oak tree is 0.539 meters in circumference, the ash tree h

stepan [7]

Answer: c. elm

Step-by-step explanation:

Given : The circumference of the oak tree= 0.539 meters

= $0.539\times100=53.9\text{ cm}$ [∵ 1 m = 100 cm] (1)

The circumference of the ash tree= 0.509 yards

$=0.509\times3\text{ feet}$ [∵ 1 yard = 3 feet]

$=0.509\times3\times 30.48\text{ cm}$ [∵ 1 foot = 30.48 cm]

$=46.54296\approx46.54\text{ cm}$ (2)

The circumference of the elm tree = 6281.70 millimeters

$=\dfrac{6281.70}{10}=628.17\text{ cm}$ (3)

The circumference of the poplar tree = 0.000385 miles

$=0.000385 \times5280\text{ feet}$ [∵ 1 mile = 5280 feet]

$=0.000385 \times5280\times30.48\text{ feet}$ [∵ 1 foot = 30.48 cm]

$=61.959744\approx61.96\ \text{ cm}$ (4)

From (1) , (2) , (3 ) and (4) it is clear that

46.54< 53.9 < 61.96 < 628.17

Hence, the elm tree has the greatest circumference.

5 0

3 years ago

Square root of 32 x square root of 1 over 18

lisov135 [29]

<h3>Solution:</h3>

$\sqrt{32} \times \sqrt{ \frac{1}{18} } \\ = \sqrt{32} \times \frac{ \sqrt{1} }{ \sqrt{18} } \\ = \sqrt{32} \times \frac{1}{ \sqrt{18} } \\ = \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} } \\ = \frac{ \sqrt{ {2}^{2} \times {2}^{2} \times 2} }{ \sqrt{2 \times {3}^{2} } } \\ = \frac{2 \times 2 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4}{3}$

<h3>Answer:</h3>

$\frac{4}{3}$

<h3>Hope it helps...</h3>

ray4918 here to help

7 0

2 years ago