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Whitepunk [10]
3 years ago
13

A buyer anticipates a house payment of $1,000 per month, with monthly homeowner association fees of $150. The buyer also has a c

ar payment of $400 per month. If the buyer earns a monthly gross income of $5,000, what is the total debt ratio?
Mathematics
1 answer:
Digiron [165]3 years ago
6 0

Answer:

Step-by-step explanation:

The buyer anticipates a house payment of $1,000 per month, with monthly homeowner association fees of $150. The buyer also has a car payment of $400 per month. If the buyer earns a monthly. This means that the buyer's monthly debt payments is

1000 + 150 + 400 = $1550

Debt ratio = monthly debt payments/monthly gross income

If the buyer earns a monthly gross income of $5,000, then

Debt ratio = 1550/5000

= 0.31

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Answer: 9:20

Step-by-step explanation:

After 25 minutes, Nico should take them out, so 9:20.

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Kobotan [32]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid (R) on the X-axis?</h3>

If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

From the given graph:

The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

here:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8)  from the graph, we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

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Similarly, the change in polar coordinates is:

  • x = rcosθ,
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where;

  • x² + y² = r²  and dA = rdrdθ

Therefore;

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  • ⇒ r = 0   to   r = 2/cosθ
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Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

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2. Now you divide the first price ($50) by the desired price ($1). This one is easy because 50 / 1 = 50, but I'm putting this here for future reference in case you need to solve a problem that has a desired price that's greater than $1.

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