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soldier1979 [14.2K]

3 years ago

9

A company spends $80 to set up their printer to print a specific T-shirt design. The company charges $10 per shirt. Which inequa

lity best represents x, the number of T-shirts the company needs to sell to pay for set-up costs and earn a profit of at least $200?

1 answer:

Vlad [161]3 years ago

7 0

Answer:

10x + 80 greater than or ewual to 200

Step-by-step explanation:

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Help i have no idea how to solve this

ASHA 777 [7]

Answer:

AB =24

Step-by-step explanation:

So, since all the sides are equal, you can just take two of the sides and set em equal to each other to find x and then, solve for AB

4x+8 =6x

8= 6x-4x

8=2x

8/2 =x

x= 4

Now, find AB, which is 4x+8

4(4) + 8

16+8 = 24

Hope this helps!

Please mark brainliest if you think I helped! Would really appreciate!

5 0

4 years ago

The sum of two numbers is 200 and the two numbers are in a ratio of 4:6. What are the two numbers?

eimsori [14]

Answer:

Let's call these numbers 4x and 6x, sum of 4x and 6x will be equal to 200, meaning 10x=200, If we divide both sides by 10, x will be equal to 20 and, the larger number 6x will be equal to, 6*20=120

Step-by-step explanation:

7 0

3 years ago

Find the perimeter of the following shape (show all work and box your final answer):

Paraphin [41]

<h3>Answer: 11x + 6y + 11</h3>

=========================================

Work Shown:

To find the perimeter, we add up all the exterior side lengths.

P = perimeter

P = (side1) + (side2) + (side 3)

P = (2y-3x-3) + (12+5x+7y) + (9x-3y+2)

P = (-3x+5x+9x) + (2y+7y-3y) + (-3+12+2)

P = 11x + 6y + 11

5 0

3 years ago

The answer to the picture below is 1 right?

Zigmanuir [339]

Yes, for any solution or value for m the answer would be 1 because any number, rational or irrational, to the power of zero always always ALWAYS is one. Hope this helps!

3 0

3 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

3 years ago