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pentagon [3]
3 years ago
12

Which dimensions cannot create a triangle? a three sides measuring 6 cm, 8 cm, and 10 cm b three angles measuring 40 degrees, 70

degrees, and 65 degrees c three angles measuring 10 degrees, 25 degrees, and 145 degrees d three sides measuring 9 m, 15 m, and 9 m
Mathematics
2 answers:
NISA [10]3 years ago
7 0

Answer:

A,C,D are triangles, B is not.

Step-by-step explanation:

Let 3 sides of a triangle be a,b,c.

A triangle have the sum of 3 angles = 180 degree

and

a-b<c<a+b (similar for a and b)

a.<u> </u><u>three sides measuring 6 cm, 8 cm, and 10 </u><u>cm</u><u> </u>

Satisfied the a-b<c<a+b property -> triangle

b. <u>three angles measuring 40 degrees, 70 degrees, and 65 </u><u>degrees</u>

<u> </u>Total of 3 angles = 40+70+65 = 175 > 180

-> not triangle

c. <u>three angles measuring 10 degrees, 25 degrees, and 145 degrees</u>

Total of 3 angles = 10+25+145 = 180

-> triangle

d. <u>three sides measuring 9 m, 15 m, and 9 m</u>

Satisfied the a-b<c<a+b property -> triangle

dlinn [17]3 years ago
3 0

Answer:

C

All triangle must equal 180, 40 + 70 + 65 = 175

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The data below consists of the heights (in inches) of 20 randomly selected women. Find the 20% trimmed mean of the data set. Rou
fenix001 [56]

Answer:

> x<-c(67, 68, 64, 61, 65, 64, 70, 67, 62, 63, 61, 64, 75, 67, 60, 59, 64, 68, 65, 71)

> length(x)

[1] 20

> mean(x, trim = 0.2)

[1] 65

Step-by-step explanation:

For this case we have the following dataset:

67 68 64 61 65 64 70 67 62 63 61 64 75 67 60 59 64 68 65 71

We can calculate the trimmed mean by hand or using R. For the first case we need to order the data on increasing way like this:

59 60 61 61 62 63 64 64 64 64 65 65 67 67 67 68 68 70 71 75

Now since we need the 20% trimmed mean we need to remove 10% of the data for the upper and the lower tail. Since we have 20 data values 20*0.1=2 observations are required to remove for each tail so our new dataset would be:

61 61 62 63 64 64 64 64 65 65 67 67 67 68 68 70

And we can calculate the trimmed mean using the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{16} =65

And if we use R we can use the following code:

> x<-c(67, 68, 64, 61, 65, 64, 70, 67, 62, 63, 61, 64, 75, 67, 60, 59, 64, 68, 65, 71)

> length(x)

[1] 20

> mean(x, trim = 0.2)

[1] 65

And as we can see both results are the same.

4 0
3 years ago
Constructive proof: There exists an integer x such that: (x^3)/5 &gt; x^2
Lana71 [14]

Answer:

x>5

Step-by-step explanation:

We are asked to find an integer x such that \frac{x^3}{5}>x^2.

First of all, we will multiply both sides of inequality by 5.

\frac{x^3}{5}>x^2  

\frac{x^3}{5}*5>5*x^2  

x^3>5x^2  

Divide both sides by x^2:

\frac{x^3}{x^2}>\frac{5x^2}{x^2}

x>5

Therefore, the value of x is any number greater than 5.

3 0
3 years ago
A company performs linear regressions to compare data sets of two similar products. If the residuals for brand A form an increas
Radda [10]
I think the correct answer would be B. If the residuals for brand A form an increasing curve, and the residuals for brand B form a U-shaped pattern, then neither of the data is likely to be linear. In order to be linear, the residuals of both data set should be, more or less, linear or approaching linearity in nature. Therefore, the linear regression that was done would not give good results since it is only applicable to linear data sets. Also, you can say that the relation of the data sets of the products are not linear. It would be best to do a curve fitting for both sets by using different functions like parabolic functions.
7 0
3 years ago
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harina [27]
Remember previous range was from -1 to 1
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3 0
3 years ago
Two turtles race. The speed of the first is 4 1/ 2 inches per minute and the speed of the other is 5 inches per minute How far a
RSB [31]

Answer:

(a) 1.5 inches

(b) 2.5 inches

(c) 5 inches

Step-by-step explanation:

speed of first turtle = 4 1/2 inches per  minute = 9/2 inches per minute

speed of the second turtle = 5inches per minute

distance = speed x time

(a) Distance traveled by first turtle in 3 minutes

s = 9/2 x 3 = 13.5 inches

distance traveled by second turtle in 3 minutes

s' = 5 x 3 = 15 inches

So, the gap is

s'- s = 15 - 13.5 = 1.5 inches

(b) Distance traveled by first turtle in 5 minutes

s = 9/2 x 5 = 22.5 inches

distance traveled by second turtle in 5 minutes

s' = 5 x 5 = 25 inches

So, the gap is

s'- s = 25 - 22.5 = 2.5 inches

(c) Distance traveled by first turtle in 10 minutes

s = 9/2 x 10 = 45 inches

distance traveled by second turtle in 10 minutes

s' = 5 x 10 = 50 inches

So, the gap is

s'- s = 50 - 45 = 5 inches

6 0
3 years ago
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