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stealth61 [152]
2 years ago
5

Celia simplified the expression Negative 4 x (1 minus 3) minus (2 x + 2). She checked her work by letting x = 5 in both expressi

ons. Her work for the original expression is shown below.
Negative 4 x (1 minus 3) minus (2 x + 2) = negative 4 (5) (1 minus 3) minus (2 (5) + 2) = negative 20 (negative 2) minus 12 = 40 minus 12 = 28.


Celia knows that the simplified expression should also equal 28 when x = 5. Which shows Celia’s simpllifed expression?
–6x – 1
–6x + 2
6x + 1
6x – 2
Mathematics
1 answer:
guapka [62]2 years ago
8 0

Answer:

6x-2

Step-by-step explanation:

-4x(1-3)-(2x+2)

= 4x+12x-2x-2

6x-2

(simplify)

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For a scientific experiment a physicist must make sure that the temperature of a metal does not get colder than -100c or the met
kati45 [8]
What’s the question???
5 0
3 years ago
Aaron claims the same answer could also be found by adding either –5 + 3 or –3 + 5.
Debora [2.8K]

Answer:

Step-by-step explanation:

-5 + 3 = -2  -5 is larger

5 + (-3) = 2   5 is larger

2 is larger than -2

8 0
3 years ago
Read 2 more answers
Please help, thank you! ​
DochEvi [55]

we know angle RLP= 100⁰

also

angle RLP+ angle RLB=180⁰(Linear pair)

=>100⁰+angleRLB= 180⁰

=> angle RLB=80⁰

since BR and LR are equal, angle RBL and angle RLB are equal

therefore angle RBL is also equal to 80⁰

using angle sum property of triangles we know that the sum of all angles in a triangle is equal to 180⁰

=>angle BRL+angle RBL+angle RLB= 180⁰

=> angle BRL+80⁰+80⁰=180⁰

=>angle BRL = 180⁰-160⁰

=>angle BRL= 20⁰

I'm sorry it took me some time I'm a slow typer

4 0
3 years ago
Read 2 more answers
4. Find the sum of all the numbers from 100 to 199 that are not divisible by 13.
Ierofanga [76]

There are 100 numbers in the range 100-199. Find the smallest and largest multiple of 13 in this range. We have

104 = 8•13

195 = 15•13

so there are 15 - 8 + 1 = 8 multiples of 13 between 100 and 199.

Then the sum we want is

\displaystyle \sum_{k=100}^{199} k - \sum_{\ell=8}^{15}13\ell

or equivalently,

(100 + 101 + 102 + … + 199) - 13 (8 + 9 + … + 15)

To compute these sums, recall the following formula:

\displaystyle \sum_{i=1}^n i = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2

Then

\displaystyle \sum_{k=100}^{199} k = \sum_{k=1}^{199} k - \sum_{k=1}^{99} k = \frac{199\cdot200}2 - \frac{99\cdot100}2 = 14,950

and

\displaystyle \sum_{\ell=8}^{15} 13\ell = 13 \left(\sum_{\ell=1}^{15} \ell - \sum_{\ell=1}^7 \ell\right) = 13 \left(\frac{15\cdot16}2 - \frac{7\cdot8}2\right) = 1,196

which means the sum we want is 14,950 - 1,196 = 13,754.

7 0
2 years ago
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