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scoray [572]
3 years ago
15

5x+4)=10x+6 step by step explanation solve and what solution is

Mathematics
2 answers:
marshall27 [118]3 years ago
3 0

Answer:

subtract 10x from both sides

5x + 4 = 10x + 6

-10x        -10x

subtract 4 from both sides

-5x + 4 = 6

<u>        -4    -4</u>

-5x  =  2

divide -5 from both sides

x = -2/5

Step-by-step explanation:

Mandarinka [93]3 years ago
3 0

Answer:

Step-by-step explanation:

5x+4  = 10x +6  

5x -10x = 6 -4

-5x      = 2

x          = 2 /-5

check    

5x + 4 = 10x +6  

5(-2/5 ) +4 =10 (-2/5 ) +6

-2 +4         = -4 +6

      2        =   2

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I REALLY NEED HELP PLEASE
Nezavi [6.7K]

Answer:

10

Step-by-step explanation:

given

\frac{s + ( - 7)}{ - 1}

we first need to simplify the expression before we find it's value when s=-3

positive times negative=negative

so the equation becomes

\frac{s - 7}{ - 1}

substituting s=-3 into the equation.

\frac{ - 3 - 7}{ - 1}

=

\frac{ - 10}{ - 1}

=the negatives cancel out leaving

= 10

7 0
3 years ago
First you to find the worksheet and download it<br> plase I need help
Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = 3^{x + 2}

The asymptote is given as x → -∞, f(x) = 3^{x + 2} → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = 3^{0 + 2} = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = 5^{1  - x}

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = 5^{1  - 0} = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = 2^{x + 3} - 1

The asymptote is 2^{x + 3}  → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) =  2^{0 + 3} - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, 2^{x + 3} - 1 = 0

2^{x + 3} = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2

The asymptote is \left (\dfrac{1}{2} \right)^{x - 2} → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6

The y-intercept is (0, 6)

7 0
3 years ago
What is the perimeter of the figure?
Monica [59]
Hey there,

So when finding the perimeter, we do addition.

So . . .

20 + 12 + 18 + 7+ 13+6

Your correct answer would be 76

Hope this helps.
~Jurgen

7 0
3 years ago
Read 2 more answers
A bag contains purple marbles and red marbles, 34 in total. The number of purple marbles is 2 more than 3 times the number of re
Irina-Kira [14]

Answer:

There are 26 purple marbles in the bag.

Step-by-step explanation:

Firstly, you have to make an expression in terms of x where x represent red marbles. Given that the question says purple marbles is 2 more than 3 times the number of red marbles. So the expression is :

Let red marbles = x,

purple = 2 + 3x

red = x

Next, given that the total marbles in the bag is 34 so you have to add both marbles together and solve the value of x :

2 + 3x + x = 34

4x = 32

x = 32 \div 4

x = 8

Lastly, you have to substitute the value of x into the expression of purple marbles :

Let x = 8,

purpe = 2 + 3(8)

purple = 26

7 0
3 years ago
My grandma can beat you in a boxing match and she is 98
CaHeK987 [17]

Answer:

I can believe it. she stronk

8 0
3 years ago
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