Answer:
16 bicycles and 21 tricycles
Step-by-step explanation:
Both bicycles and tricycles have 1 set of handlebars. Bicycles have 2 wheels while tricycles have 3.
Using this information, set up a system of equations, where b is the number of bicycles and t is the number of tricycles:
b + t = 37
2b + 3t = 95
Solve by elimination by multiplying the top equation by -2:
-2b - 2t = -74
2b + 3t = 95
t = 21
Then, plug in 21 as t into one of the equations:
b + t = 37
b + 21 = 37
b = 16
So, there are 16 bicycles and 21 tricycles
Answer:
12/100
Step-by-step explanation:
This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
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If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
