127.5 is 250% of what?

Need help with this. Write an equation that is parallel to the line whose equation is y = −8x − 7?

shutvik [7]

Answer:

Problem 4: y = -8x+b

Problem 5: C: 3x-2

Step-by-step explanation:

<u>Problem 4:</u>

The given line is in slope intercept form.

The slope-intercept form is:

$y = mx+b$

Here the co-efficient of x is the slope of the line. Comparing the given equation with general form

m = -8

Two parallel lines have same slope so the slope of line will be -8.

$y=mx+b\\y = -8x+b$

b can be any positive or negative integer as we don't know any point on the line parallel to given line.

<u>Problem 5:</u>

Slope = 3

y-intercept = -2

Slope intercept of line is given by:

$y = mx+b$

here m is slope and b is y-intercept

Putting the values

$y = 3x-2$

Option C: y=3x-2 is the correct answer

Hence,

Problem 4: y = -8x+b

Problem 5: C: 3x-2

6 0

3 years ago

The graph of which of the following will be parallel to the graph of y = 2x – 4?. . . A.. 2x + y = 4. B.. 4x – 2y = –12. C.. y =

storchak [24]

Parallel lines have the same gradient.
The equations are either in the form y = mx+b (m is the gradient)
or in general form ax + by + c = 0 (-a/b)

The gradient of y = 2x - 4 is 2.

The answer is B (gradient = -4/-2 = 2)

7 0

3 years ago

Read 2 more answers

Part A. Write an equation of a line that is perpendicular to the line y = 2/3x + 5 and passes through the point (4, 0).

fenix001 [56]

Answer:

$y = -\frac{3}{2}x+6$

Step-by-step explanation:

Given:

The given equation of the line $y = \frac{2}{3} x + 5$ that passes through the point (4, 0).

Part A.

The equation of the line.

$y=mx+c$ -----------(1)

Where:

m = Slope of the line

c = y-intercept

The given equation of the line.

$y = \frac{2}{3} x + 5$

Comparing the given equation with equation 1.

The slope of the line is $m=\frac{2}{3}$ and y-intercept $c = 5$

We know that the slope of the perpendicular line is $(-\frac{1}{m})$ .

So the slope of the perpendicular line is $(m=-\frac{1}{\frac{2}{3}}=-\frac{3}{2})$ .

Using point slope formula we write the equation of the perpendicular line that passes through the point (4, 0).

$y-y_{1} = m(x-x_{1}$

Now we substitute the slope of the perpendicular line $m=-\frac{3}{2}$ and $y_{1} = 0, x_{1}=4$ from point (4, 0) in above equation.

$y-0 = -\frac{3}{2}(x-4)$

$y = -\frac{3}{2}x-(-\frac{3}{2}\times 4)$

$y = -\frac{3}{2}x-(-3\times 2)$

$y = -\frac{3}{2}x-(-6)$

$y = -\frac{3}{2}x+6$

Therefore the perpendicular line equation is $y = -\frac{3}{2}x+6$ .

Part B.

1. The slope of the perpendicular line is $m=-\frac{3}{2}$ .

2. The y-intercept of the perpendicular line is 6.

3. The equation of the line $y = -\frac{3}{2}x+6$ is perpendicular to the equation of line $y = \frac{2}{3} x + 5$ .

6 0

3 years ago

Consider the equation 9x+3=x−1. Squaring the left side and simplifying results in _______. Squaring the right side and simplify

bixtya [17]

Answer:

The first blank is 81 $x^{2}$ +9=x-1

The second blank is 9x+3=x^2-1

Step-by-step explanation:

For the first part, you must set up the equation (9x+3)^2 then you must multiply the exponent to the inside exponents $9^{2} x^{2}$ + $3^{2}$ next, simplify.