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Mekhanik [1.2K]
3 years ago
11

The length of a line segment is 13 units. One end point of the line segment is (-3,7). Find four points that could be the other

end points of the line segment.
Mathematics
1 answer:
monitta3 years ago
3 0

Answer:

( -16,7 ) , ( 10,7 ) , ( -3,20 ) and ( -3,-6 )

Step-by-step explanation:

We are given a line segment with one end point ( -3,7 ) and length 13 units.

So, there are many possibilities for the other end points.

Four of them are:

A. 13 units left i.e. ( -3-13,7 ) = ( -16,7 )

B. 13 units right i.e. ( -3+13,7 ) = ( 10,7 )

C. 13 units up i.e. ( -3,7+13 ) = ( -3,20 )

D. 13 units down i.e. ( -3,7-13 ) = ( -3,-6 ).

So, the other four end points could be ( -16,7 ) , ( 10,7 ) , ( -3,20 ) and ( -3,-6 ).

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Find a_1 and d for an arithmetic sequence with these terms. a_4=9and a_7=18
jonny [76]
\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_4&9\\
a_5&9+d\\
a_6&(9+d)+d\\
&9+2d\\
a_7&(9+2d)+d\\
&9+3d=\underline{18}
\end{array}\\\\
-------------------------------\\\\
9+3d=18\implies 3d=9\implies d=\cfrac{9}{3}\implies \boxed{d=3}

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=7\\
d=3
\end{cases}
\\\\\\
a_7=a_1+(7-1)d\implies 18=a_1+(7-1)3\implies 18=a_1+18
\\\\\\
18-18=a_1\implies \boxed{0=a_1}
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4 years ago
Total employment for sheet metal workers in 2016 is projected to be 201,000. If this is a 6.3% increase from 2006,
anastassius [24]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
The Montague family and their neighbors the Capulets attended the school play together. The Montagues bought two adult tickets a
9966 [12]

Answer:

The cost for adult tickets be represented by x = $5

The cost for student tickets be y = $2

Step-by-step explanation:

Let the cost for adult tickets be represented by x

the cost for student tickets be y

The Montague family and their neighbors the Capulets attended the school play together. The Montagues bought two adult tickets and three student tickets for $16.

= 2x + 3y = 16... Equation 1

The Capulets purchased three adult tickets and two student tickets for $19.

3x + 2y = 19 ..... Equation 2

How much was each adult and student ticket?

2x + 3y = 16... Equation 1

3x + 2y = 19 ..... Equation 2

We solve using Elimination method

Multiply Equation 1 by 2 and Equation 2 by 3 to eliminate u

4x + 6y = 32..... Equation 3

9x + 6y = 57.... Equation 4

Subtract Equation 4 from 3

-5x = -25

x = 25/5

x = $5

2x + 3y = 16... Equation 1

Since x = $5

2($5) + 3y = 16

10 + 3y = 16

3y = 16 - 10

3y = 6

y = 6/3

y = $2

Therefore:

The cost for adult tickets be represented by x = $5

The cost for student tickets be y = $2

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3 years ago
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3/4 is the slope!! good luck!!
5 0
3 years ago
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