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statuscvo [17]
2 years ago
14

A subway train is traveling at a rate of 22.4 m/s. Brakes are applied and it slows down at a constant rate of 3.5 m/s2 until it

stops at a station. Find the total distance traveled while braking.

Mathematics
1 answer:
WARRIOR [948]2 years ago
6 0

You use the equation Final Velocity²= (Initial Velocity)² 2(Acceleration)(Distance). You plug in what you have 0²=22.4² X 2(-3.5)(D) and solve for D which is 71.68m or about 72m.

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(x^2−1)(3x−4)(3x+4) what is the product
Andrei [34K]

Answer:

9x^4-25x^2+16

Step-by-step explanation:

(x^2−1)(3x−4)(3x+4)=(*)

(x^2−1)((3x)^2−4^2) =

(x^2 - 1)(9x^2-16)=

x^2*9x^2 - x^2*16 - 1*9x^2 +16=

9x^4-16x^2-9x^2+16=

9x^4-25x^2+16

(*) (A-B)(A+B) =A^2 - B^2

6 0
2 years ago
Find the missing side of this right
navik [9.2K]

Answer:

x = 13

Step-by-step explanation:

First start with the blank equation

a^{2} + b^{2} = c^{2}

Plug in the legs and hypotenuse. Remember c squared is always the hypotenuse.

5^{2} + 12^{2} = c^{2}

Then solve

25 + 144 = c^{2}

169 =c^{2}

\sqrt{169} = \sqrt{c^{2} }

c = 13

3 0
3 years ago
The sum of two consecutive integers is one less than three times the smaller integer. Find the two integers.
Minchanka [31]

The small number is 2.

The large number is 3.

<u>Step-by-step explanation:</u>

Let the two consecutive numbers be x and x+1.

  • x be the small integer.
  • x+1 be the large integer.

The sum of these two consecutive integers = small integer + large integer

The sum of these two consecutive integers is x+x+1 = (2x+1)

It is given that,

  • The sum of two consecutive integers is one less than three times the smaller integer.
  • This means that, (2x+1) is one less than three times the smaller integer.
  • Here, the small integer is represented as x.

<u>Therefore, it can determined that :</u>

(2x+1) = 3x-1

Keeping x term on one side and constants on other side,

3x-2x = 1+1

x = 2

Therefore, the small number is 2 and the large number is x+1 = 3.

3 0
3 years ago
Based only on the information given in the diagram, which congruence
romanna [79]
<h3>1 Answer: Choice D) SAS</h3>

=================================================

Explanation:

LA stands for Leg Angle. More specifically, the angle is an acute angle. This theorem only works for right triangles. We see that ED = LK which is one pair of congruent leg segments. So that takes care of the L part of LA. However, we don't know anything about the acute angles. We don't know if angle E = angle L, or if angle F = angle M, or something along those lines. We need angle markers to tell us or not.

In short, we only have half the info needed for LA, so we must cross choice A off the list.

----------------

HA stands for hypotenuse angle, or hypotenuse acute angle, and this rule only applies for right triangles. We don't know anything about the hypotenuse lengths if they are the same or not.

Similar to choice A, we don't know anything about the acute angles either.

Those two facts mean we must cross off choice B.

----------------

AAS stands for Angle Angle Side. The order is important because the side is not between the angles. The diagram only shows one pair of angles that are congruent to one another. That pair being the 90 degree angles indicated with the square marker. We don't have another pair of angles, so we cannot use AAS.

Cross choice C off the list.

-----------------

We can use SAS because we have two pairs of congruent sides and one pair of congruent angles.

The congruent sides are

  • ED = LK (double tickmarks)
  • DF = KM (single tickmarks)

That takes care of the two "S"s of "SAS". The "A" would be those two right angles which are congruent to one another. The angles are between the congruent sides which is important. Recall that SSA is not a valid congruence theorem.

So that's why choice D is the only answer.

-----------------

Side note: We could use the LL theorem, where L stands for leg, since we are given two pairs of congruent legs for each triangle. Like LA and HA, this only applies to right triangles. LL is a special case of SAS. However, LL isn't listed so we'll just be sticking with SAS as the only answer.

8 0
3 years ago
Can you help me in write the perimeter of the triangle in a simplest form
Angelina_Jolie [31]

I got 6x+3



The three equations are:

(2x-6) + (3x+1) + (x+8) =perimeter

2x+3x+x/1x=6x

-6+1+8= 3

8 0
2 years ago
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