Question

A camera manufacturer spends $2,250 each day for overhead expenses plus $6 per camera for labor and materials. The cameras sell for $16 each. How many cameras must the company sell in one day to equal its daily costs? If the manufacturer can increase production by 50 cameras per day, what would their daily profit be?

Answer 1

2250 + 6x = 16x
2250 = 16x - 6x
2250 = 10x
2250/10 = x
225 = x <=== they must sell 225 cameras to equal daily costs

if they increase production by 50.......x = 225 + 50 = 275
16(275) - 6(275) - 2250 = 4400 - 1650 - 2250 = 4400 - 3900 = 500.
Their daily profit would be $500.

Answer 2

Answer:

225 cameras

$500 profit

Step-by-step explanation:

The daily cost for overhead expenses is $2250 plus $6 for labor and materials:

Let the total amount spent per day be y:

$=2250+6x=y$ (1)

If the camera sells for $16 we must determine how many must be sold to make 2250+6x. We can write another expression in terms of x and y:

$y=16*x$  (2)

We can substitute equation 2 into equation 1 and solve x:

$16*x=2250+6*x$

$x=225$

The company must sell 225 cameras at a price of $16

If the manafacturer increases the production by 50 a day the daily profit would be:

$(225+50)*16=4400$

The the profit is the amount made subtracted from the the daily expenses:

$4400-(2250+6*275)=500$

The daily profit will be $500