Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So,
is 37°. We can see from the diagram that
would be
143°.
Also, the new bearing is N 25°E. So,
would be 25°.
Now we can find
. As the sum of the internal angle of a triangle is 180°.

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
2x - 2y
Step-by-step explanation:
Multiply by 1
combine like terms
Combine the second
rearrange terms
Then you should come up with the sloution 2x - 2y
Answer:
D. (x - 2)(x + 2)
Step-by-step explanation:
Look at the graph, when y = 0, x = - 2 and x = 2, vertex = -4
OK so x = -2 means x + 2 = 0
and x = 2, means x - 2 = 0
So
answer :D. (x - 2)(x + 2)
Answer:
D) -9/4
Step-by-step explanation:
-4(3)³/3(4)²
-4(27)/3(16)
-108/48
divides both by 12
- 9/4
Answer:
D is the answer
Step-by-step explanation:
Well 35 dollar one time fee
plus 15 per hour
If used 1 hour 15+35=50