Given the following table that gives data from a linear function:
![\begin {tabular} {|c|c|c|c|} Temperature, $y = f(x)$ (^\circ C)&0&5&20 \\ [1ex] Temperature, $x$ (^\circ F)&32&41&68 \\ \end {tabular}](https://tex.z-dn.net/?f=%5Cbegin%20%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7C%7D%0ATemperature%2C%20%24y%20%3D%20f%28x%29%24%20%28%5E%5Ccirc%20C%29%260%265%2620%20%5C%5C%20%5B1ex%5D%0ATemperature%2C%20%24x%24%20%28%5E%5Ccirc%20F%29%2632%2641%2668%20%5C%5C%20%0A%5Cend%20%7Btabular%7D)
The formular for the function can be obtained by choosing two points from the table and using the formular for the equation of a straight line.
Recall that the equation of a straight line is given by
Using the points (32, 0) and (41, 5), we have:
By better I am assuming you meant faster so,
18 ÷ 2 = 9
22 ÷ 2.5 = 8.8
9 > 8.8
therefore Emily has the faster rate.
Answer:
∠A ≈ 66°
∠B ≈ 24°
AC ≈ 1.2
Step-by-step explanation:
SOH CAH TOA and the Pythagorean theorem are useful tools for solving right triangles. The first tells you ...
Sin = Opposite/Hypotenuse
For ∠A, that means ...
sin(A) = BC/AB = 2.7/2.95
The inverse sine function (sin⁻¹ or arcsin) is used to find the angle from its sine value, so ...
A = arcsin(2.7/2.95) ≈ 66°
Likewise, the ratio for angle B involves the adjacent side:
Cos = Adjacent/Hypotenuse
cos(B) = BC/AB = 2.7/2.95
B = arccos(2.7/2.95) ≈ 24°
Of course, angles A and B are complementary, so once you know angle A, you know that angle B is ...
∠B = 90° -∠A = 90° -66° = 24°
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The Pythagorean theorem can be used to find the unknown side. It tells you ...
AB² = AC² + BC²
2.95² = AC² + 2.7²
AC = √(2.95² -2.7²) ≈ 1.2
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These calculations are shown in the attachment using a TI-84 graphing calculator set to degrees mode. Any scientific or graphing calculator will do.
To find the area of this just add the units I believe which is 21
Hope this helps good luck. Not sure if this is 100% right my last year teacher was a sucky one
Answer:
true
Step-by-step explanation:
1/10=0.1
0.1*2=0.2
