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3 years ago

How do i solve these questions? can someone please tell me thanks :)

Mathematics

1 answer:

Vika [28.1K]3 years ago

6 0

To find the area of this just add the units I believe which is 21
Hope this helps good luck. Not sure if this is 100% right my last year teacher was a sucky one

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Simplify the expression below 6m^5+15m^2/3m^2

densk [106]

Answer:6m^5+5

Step-by-step explanation:

To simplify 6m^5+15m^2/3m^2

We get

6m^5+5

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3 years ago

In triangle ΔABC, ∠C is a right angle and CD is the height to

Zina [86]

Answer:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles $m\angle CDB=m\angle CDA=90$ °

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

$m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha$

From ΔCBD,

$m\angle CBD$ is same as $m\angle B$ .

So, $m\angle CBD=90-\alpha$

$m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha$

Now, from ΔCAD,

$m\angle CAD$ is same as $m\angle A$

So, $m\angle CAD=\alpha$

$m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha$

Hence, the unknown angles of both the triangles are:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

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2 years ago

2 There are x fish in a pond.

Akimi4 [234]

Answer:

x+5

Step-by-step explanation:

We are adding fish

There were x and then we added 5

There are now

x+5

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3 years ago

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Hunter-Best [27]

Answer:

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2 years ago

Which object has the mass of about one kilogram?

stira [4]

Answer:

A dictionary has the mass of about 1 killo so the book!

Step-by-step explanation:

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2 years ago

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