The interval where the function is nonlinear and decreasing is 0 < x < 4
<h3>How to determine the interval where the function is nonlinear and decreasing?</h3>
The straight lines on the graph are the intervals where the graph is linear
This means that the straight lines on the graph will not be considered
Considering the curve, the graph decrease from x = 0 to x = 4
This can be rewritten as:
0 < x < 4
Hence, the interval where the function is nonlinear and decreasing is 0 < x < 4
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Answer:
P(S or T)= 3/4
Step-by-step explanation:
Given:
S and T are mutually exclusive events
find P(S or T)
P(S or T)= P(S) + P(T)
= 1/3 +5/12
=4+5/12
=9/12
=3/4 !
Answer:
65/24 or 2 17/24
Step-by-step explanation:
4 1/8 - 1 5/12
= 33/8 - 17/12
= 33/8(3/3) - 17/12(2/2)
= 99/24 - 34/24
= 65/24
A= $8000 (2.718)∧.06x5 (.06 x 5 = .3)
Order of operations says to do 2.718∧.3 first and then multiply by 8000
I get 10,798.53 answer b
Any natural or whole number works I believe. 1,2,3,4,5,6,7,8,9,10,11etc. Hope this helps