Make a proportion of the diameter over the circumference.
185 feet / 580 feet = x / 10 feet
580x=1850
x= about 3.2
Diameter= about 3.2 feet
Hope this helps :)
Answer:
1/2 of an hour
Step-by-step explanation:
Well firstly we must find the amount of minutes spent watching. Which is 3 * 60 = 180mins.Then we find 1/6 of 180 = 30We now know Cody has watch 30 minute of the movie.To find what fraction this is of an hour we divide it by minutes in an hour:30/60 which is 1/2Therefore the answer is 1/2 of an hour
Step-by-step explanation:
1/2 × (p+9) is the algebraic expression.
Answer:
Distance from the airport = 894.43 km
Step-by-step explanation:
Displacement and Velocity
The velocity of an object assumed as constant in time can be computed as

Where
is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as


The displacement of the plane in 2 hours is


Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are


The displacement in 1 hour is


The total displacement is the vector sum of both



The distance from the airport is the module of the displacement:


Solution
Problem 6
For this case we can do this:
12, 16,__, 14, 8, 7
We can solve for x like this:


Problem 7
F