Answer:
Step-by-step explanation:
The given function is
We want to find all values of x for which:
f(x) is greater than or equal to 14.
This implies;
Subtract 13 from both sides;
By definition of the absolute value function,
Divide through the first inequality and and reverse the inequality sign:
One hundred fifty two thousands is 152.000
and 5 million is 5000000
so from this result that 5 million is greater
918.642 x 1/10 = 918.642 x 0.1 = 91.8642
Answer:
1/20
Step-by-step explanation:
In Scarlette grade 1/5 of the students have a sister.
Of the students who have a sister 1/4 also have a brother
Therefore fraction if students in Scarlet's grade who had both brothers and sister can be calculated as follows
= 1/5 ×1/4
= 1/20
Firstly let's find the dimension of this large rectangle:(given)
Area of Rectangle = 660 x 66 =43,560 ft²
And we know that 1 acre = 43,560 ft², then each rectangle has an area of 1 acre & the 20 acres will correspond to 20 x 43560 = 871,200 ft²
We know that the 20 acres form a rectangle. We need to know what is their disposition:
1) We would like to know the layout of the rectangles since we have 4 possibilities FOR THE LAYOUTS
Note that W=66 & L=666 = 43,956 ft²/ unit )
lay out shape could be either:(in ft)
1 W by 20 L (Final shape Linear 66 x 13320 = 879,120) or
2 W by 10 L (Final shape Stacked 132 x 6660 = 879,120) or
4 W by 5 L (Final shape Stacked 264 x 3330 = 879,120) or
2) We would like to know the number of participants so that to allocate equal space as well as the pedestrian lane, if possible, if not we will calculated the reserved space allocated for pedestrian/visitors)
3) Depending on the shape given we will calculate the visitor space & we will deduct it from the total space to distribute the remaining among the exhibitors.
4) (SUGGESTION) Assuming it's linear, we will reserve
20ft x 13320 ft = = 266,400 ft² and the remaining 612,720 ft² for exhibitors
5) Depending on the kind of the exhibition, we will divide the 612,720 ft² accordingly
6) How can we select the space allocated for each exhibitor:
the 617,720 ft² could be written as a product of prime factors:
612720 = 2⁴ x 3² x 5 x 23 x 37
If you chose each space will be185 ft² , then we can accommodate up to 3,312 exhibitors.
Obviously you can choose any multiple of the prime factors to specify the area allocated & to calculate the number of exhibitors accordingly
