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A frog in a well is 23 feet below the ground level. It jumps 16 feet and eats a fly (gross!).
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Using the normal distribution, it is found that there is a 0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The probability that the life span of the monitor will be more than 20,179 hours is <u>one subtracted by the p-value of Z when X = 20179</u>, hence:
Z = 0.59.
Z = 0.59 has a p-value of 0.7224.
1 - 0.7224 = 0.2776.
0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.
More can be learned about the normal distribution at brainly.com/question/24663213
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The Markup percentage is mathematically given as
M=42%
<h3>What is Mark up percentage?</h3>The markup % may be determined by dividing the gross profit of a unit (the difference between its sales price and the amount it cost to create or buy for resale) by the amount that unit originally cost. If a product sells for $12 but only costs the corporation $8 to produce it, the markup percentage for that product is 50%, which can be calculated as (12 - 8) divided by 8.
Generally, the equation for is Total cost price mathematically given as
TCP= Pay+insurance
Therefore
TCP=35.5*1.6
TCP=284/5
Generally, the equation for is Total selling price mathematically given as
TSP=89.99+7.99
TSP=97.98
In conclusion, Mark up percentage is
M=0.4202898551*100
M=42%
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