Hello from MrBillDoesMath!
Answer:
3
Discussion:
34 + 2x = 40 => subtract 34 from both sides
(34-34) + 2x = 40 - 34 => as (34-34) = 0 and 40-34 = 6
2x = 6 => divide both sides by 2
x = 6/2 = 3
Check the answer:
Does 34 + 2x = 40 if x = 3 ?
Does 34 + 2(3) = 40 ?
Does 34 + 6 = 40 ? YES! so the answer checks.
Thank you,
MrB
Answer:
g(4x) = 192x^3
Step-by-step explanation:
For this problem, f(x) is irrelevant since we are simply are dealing with g(x). We will simply replace the value of x in g(x) with 4x. So let's do that.
g(x) = 3x^3
g(4x) = 3(4x)^3
g(4x) = 3(4^3)(x^3)
g(4x) = 3(64)(x^3)
g(4x) = 192x^3
Hence, g(4x) is 192x^3.
Cheers.
Answer:
a) -12
b) 8+11x+11b-3x^2-3b^2-6xb
c)-52
Step-by-step explanation:
in a) we have to substitute the value of x with 5
in b) we substitute the value of x with (x+b) and then simplify
in c) just have to substitute x with -3
Answer:
x+4=20 is a solution to 5(x+4)=100.
Step-by-step explanation:
Following PEMDAS, divide 5 from both sides of the equation 5(x+4)=100, and you have x+4=20 remaining.
This means that both equations have the same solution.
The answer to the question
