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barxatty [35]
3 years ago
13

Please answer the question for me. I need help with this problem.

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
7 0
Don't think I am correct but it could be either C or D, because you have 3 terms in the equation. 
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Consider the function f(x) = -4x²-9x+20.<br><br> Determine f(-2)=
hoa [83]

Step-by-step explanation:

  • you just substitute (-2) into the x values of the above function
  1. f( - 2) =  - 4( - 2)^{2}  - 9( - 2) + 20 \\ f( - 2) = 22
3 0
2 years ago
Help me please I’m stuck
lisabon 2012 [21]
The x axis of the point is being translated three units to the left (going from 6 to 3)
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8 0
2 years ago
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What is the midpoint of the line segment
Karo-lina-s [1.5K]

Answer:

The answer to your question is (-1, -1)

Step-by-step explanation:

Data

A (1, -6)

B (-3, 4)

Formula

Xm = \frac{x1 + x2}{2}

Ym = \frac{y1 + y2}{2}

Process

1.- Substitute the values in the formula

x1 = 1   x2 = -3

Xm = \frac{1 - 3}{2} = \frac{-2}{2} = -1

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Ym = \frac{-6 + 4}{2} = \frac{-2}{2} = -1

2.- The midpoint is  (-1, -1)

5 0
3 years ago
Suppose f (x )right arrow 250 and g (x )right arrow 0 with ​g(x)greater than0 as x right arrow 5. Determine ModifyingBelow lim W
Rama09 [41]

Answer:

The limit is \lim_{x \to 5} \frac{250}{0} = \infty

Step-by-step explanation:

The  equation given are

     f(x)  \to  250

and   g(x) \to 0

with g(x) > 0 \ as\   x ---> 5

The objective is to obtain

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This mathematically evaluated as

        \lim_{x \to 5} \frac{250}{0}

      = \lim_{x \to 5} \frac{250}{0} = \infty

6 0
2 years ago
The common ratio in a geometric series is 4 and the first term is 3 Find the sum of the first 8 terms in the series.
kakasveta [241]
... is this working ?
6 0
3 years ago
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