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2 years ago

If Y is the midpoint of segement WZ, YZ = x + 3, and WZ = 3x-4, determine the length of segment WZ

Mathematics

1 answer:

Georgia [21]2 years ago

3 0

This is my answer! I solve it by myself, check it out!!!! Sorry for late

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Bacteria usually reproduce by a process called binary fission. In this type of reproduction, one bacterium divides to

Fed [463]

Answer:

$\large \boxed{\text{0.0462 min}^{-1}}$

Step-by-step explanation:

One formula for the reproduction of bacteria is

$\dfrac{N}{N_{0}} = e^{kt}$

Data:

N = 2

N₀ = 1

t = 15 min

Calculation:

$\begin{array}{rcl}\dfrac{N}{N_{0}}& =& e^{kt}\\\\\dfrac{2}{1}& = & e^{k\times15 \text{ min}}\\\\2 & = & e^{15k \text{ min}}\\\ln 2 & = & 15k \text{ min}\\k & = & \dfrac{\ln2 }{\text{15 min}}\\\\& = & \textbf{0.0462 min}^{\mathbf{-1}}\\\\\end{array}\\\text{The value of the constant k is $\large \boxed{\textbf{0.0462 min }^{\mathbf{-1}}}$}$

6 0

3 years ago

At dan's school,6 out of every 10 kids know how to swim. If there are 350 kids in his school,how many know how to swim?

Bogdan [553]

210 because if you multiply 10 by 35 to get 350 you have to multiply 6 by 35 then you get 210

4 0

2 years ago

Read 2 more answers

Rewrite this as a simplified fraction;<br> 0.7...=?

d1i1m1o1n [39]

Answer:

0.7777..... is 7/9

Step-by-step explanation:

use the calculator to solve this q

8 0

2 years ago

Read 2 more answers

Find the surface area of the rectangular and triangular prisms

harina [27]

Is there a picture to this????

if your just asking how to find the area of something all you need to do is multiply all the numbers together and the total is the area.
For example if its 8cm,3cm,2cm all you need to do is multiply them together
8x3x2=48 so your area is 48cm

7 0

3 years ago

An Archer shoots an arrow horizontally at 250 feet per second. The bullseye on the target and the arrow are initially at the sam

Genrish500 [490]

Answer:

Step-by-step explanation:

Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;

Range $R = U\sqrt{\frac{H}{g} }$

U is the velocity of the arrow

H is the maximum height reached = distance below the bullseye reached by the arrow.

R is the horizontal distance covered i.e the distance of the target from the archer.

g is the acceleration due to gravity.

Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?

On substitution,

$60 = 250\sqrt{\frac{H}{32}} \\\frac{60}{250} = \sqrt{\frac{H}{32}}\\\frac{6}{25} = \sqrt{\frac{H}{32}$

Squaring both sides we have;

$(\frac{6}{25} )^{2} = (\sqrt{\frac{H}{32} } )^{2} \\\frac{36}{625} = \frac{H}{32} \\625H = 36*32\\H = \frac{36*32}{625} \\H = 1.84feet$

The arrow will hit the target 1.84feet below the bullseye.

5 0

2 years ago