I can't graph the equation for you, but I can tell you where the points will be. The y-intercept is easy; 1/3×0=0 and 0-2= -2. One of your points (the y-intercept) should be at (0,-2). To find another point is slightly trickier, but all you have to do here is find a multiple of three. For the simplest one, go to 3 on the x-axis. Then, apply the equation, y=1/3x-2. Your second point should lay at (3,-1). Then, just connect those two points and extend them to show that the line is continuous. Hope I could help!
