Answer:
the 2 one is a linear and the rest are non
If
<em>f(x)</em> = <em>ax</em> ³ + <em>bx</em> ² - 5<em>x</em> + 9
then
<em>f '(x)</em> = 3<em>ax </em>² + 2<em>bx</em> - 5
Given that <em>f</em> (-1) = 12 and <em>f</em> '(-1) = 3, we get the system of equations
-<em>a</em> + <em>b</em> + 5 + 9 = 12
3<em>a</em> - 2<em>b</em> - 5 = 3
or
-<em>a</em> + <em>b</em> = -2
3<em>a</em> - 2<em>b</em> = 8
Multiply through the first equation by 2 and add it to the second one to eliminate <em>b</em> and solve for <em>a</em> :
2(-<em>a</em> + <em>b</em>) + (3<em>a</em> - 2<em>b</em>) = 2(-2) + 8
-2<em>a</em> + 2<em>b</em> + 3<em>a</em> - 2<em>b</em> = -4 + 8
<em>a</em> = 4
Substitute this into the first equation above to solve for <em>b</em> :
-4 + <em>b</em> = -2
<em>b</em> = 2
Answer:
x= - 16
Step-by-step explanation:
substitute y=0 then multuply both sides move the variable to the left and change the sign.
Answer:
ITS C STRAIGHT LINE ACROSS
Step-by-step explanation:
we know that
The fraction of each tile color can be found by dividing the number of tiles for each tile by the total number of tiles, then simplifying the fraction if possible.
Let
N----------> total number of tiles
Y---------> number of yellow tiles
B--------> number of blue tiles
P--------> number of purple tiles
we have

<u>1) Find the fraction of yellow tiles</u>
we know that
the fraction of yellow tiles is equal to

substitute the values

<u>2) Find the fraction of purple tiles</u>
we know that
the fraction of purple tiles is equal to

substitute the values

<u>3) Find the fraction of yellow tiles or purple tiles</u>
we know that
the fraction of yellow tiles or purple tiles is equal to

therefore
<u>the answer is</u>
