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2 years ago

The whole number and unit fraction of 5\6

Mathematics

1 answer:

tester [92]2 years ago

7 0

Whole number: 0.84

Unit fraction: 5/6

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Please help me Simplify 3✔️2 - ✔️2

MAXImum [283]

$\bf \stackrel{like~terms}{3\sqrt{2}-\sqrt{2}}\implies 2\sqrt{2}$

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3 years ago

The complement of (10 Points)

loris [4]

Answer:

..?

Step-by-step explanation:

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2 years ago

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Find an equation of the sphere that passes through the origin and whose center is (-2, 2, 3). Be sure that your formula is monic

Andrei [34K]

Answer:

$\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

$(x-a)^2+(y-b)^2+(z-c)^2=r^2$

Where ( $x,y,z$ ) are the points on sphere.

$(a, b, c)$ is the center of the sphere and

$r$ is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Here,

$x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2 =2 \\z_2 =3$

So, Radius is:

$r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}$

Therefore the equation of the sphere is:

$(x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

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3 years ago

Simplify 2/9 + 1/3 + 2/3=

Maurinko [17]

2/9 + 1/3 + 2/3
2/9 + 3/9 + 6/9
(2 + 3 + 6) /9
11/9

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3 years ago

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Say that a and b are the lengths of the legs of a right triangle and c is the length of the hypotenuse. Find b if a = 21 and c =

maria [59]

When the triangle is a right triangle, you can use the Pythagorean theorem. The formula would be

c^2 = a^2 + b^2

If a = 21 and c=29, thus

b^2 = c^2 - a^2
b^2 = 29^2 - 21^2
b^2 = 400
b = square root (400)
b = 20 units.

Thus, the answer is <span>D) B = 400</span>

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2 years ago

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