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givi [52]
3 years ago
13

Please help with number 14!

Mathematics
1 answer:
Elanso [62]3 years ago
3 0

Answer:

hrgbg

Step-by-step explanation:


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What is the Midpoint of CD given the coordinates C(-4,8) and D(8,-4)??
alina1380 [7]
Use this formula...
(-4 + 8) / 2 , (8 + (-4)) / 2
From there you get...
4 / 2 , 4 / 2
Simplify and you get
(2 , 2)

3 0
3 years ago
Read 2 more answers
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
3 years ago
erica watch 1/2 of a movie in the morning and she watched some at night and by the end of the day she still had 1/3 of left how
Anastaziya [24]
Convert to equivalent fractions to see
Both bottom s can be 6
So times the half by 3
And times the third by 2
1/2=3/6
1/3=2/6
So she has a total of 5/6 of the movie accounted for...
So the left over is 1/6
1/6 at nighttime
8 0
3 years ago
Which is the correct way to evaluate f(15) for the function f(x)=2(x+3)?
Thepotemich [5.8K]

Answer:

the first option

Step-by-step explanation:

Start by substituting 15 for x. Then, simplify to get f(15)=36.

cuz

f(x)=2(x+3)

f(15)=2(15+3)

= 2×18=36

gimme brainliest plz

3 0
3 years ago
Please I need help !!!!
frez [133]

Answer:

The first one is c the second is b

3 0
2 years ago
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