Answer:
Minimum value: 6 inches,
Maximum value: 8 inches.
Step-by-step explanation:
To find the minimum length of s, we need to use the minimum volume of the shipping box in the equation, so:
s_minimum = ^3√(2*108) = ^3√216 = 6 inches
The maximum value of the volume will give us the maximum value of the length:
s_maximum = ^3√(2*256) = ^3√512 = 8 inches
So the minimum value of the length is 6 inches and the maximum value is 8 inches.
Answer:
d, 3 5/8
Step-by-step explanation:
You sure seem to be asking a lot of questions lately. I'd like to see that you've been trying with these problems at least because if you can't get that first one it's almost like you missed the whole lesson.
1. 20 = 4b + 7 + 5
Add the 7 and 5.
20 = 4b + 12
Subtract 12 from each side.
8 = 4b
Divide each side by 4.
2 = b
2. 7 = 6k - 7k
6k - 7k = -1k. (the k acts as a sort of unit)
7 = -1k
Divide each side by -1.
-7 = k
3. 3.23 - 2m = 3 - 2(5m - 2)
Distribute the ×-2 to each term inside the parentheses.
3.23 - 2m = 3 - 10m + 4
Add the 3 and 4.
3.23 - 2m = 7 - 10m
Add 10m to each side.
3.23 + 8m = 7
Subtract 3.23 from each side.
8m = 3.77
Divide by 8.
m = 0.47125
4. -88/45=1/3r+2/5r
To get rid of the fractions, let's multiply everything by 45.
-88 = 15 + 18r
Subtract 15 from each side.
-103 = 18r
Divide by 18.
-103/18 = r
As a mixed number, r = -5 and 13/18
As a decimal, r = -5.7222...
Answer:
A linear relationship (or linear association) is a statistical term used to describe a straight-line relationship between two variables. Linear relationships can be expressed either in a graphical format or as a mathematical equation of the form y = mx + b. Linear relationships are fairly common in daily life.
Step-by-step explanation:
Answer:
r = 144 units
Step-by-step explanation:
The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.
Substituting the terms of the equation and the derivative of r´, as follows,

Doing the operations inside of the brackets the derivatives are:
1 ) 
2) 
Entering these values of the integral is

It is possible to factorize the quadratic function and the integral can reduced as,

Thus, evaluate from 0 to 16
The value is 