4r² - 2s³ for r = 1 and s = 5 Thanks!
2 answers:
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Answer:
Discontinuity at (-4,-2), zero at (-2,0).
Step-by-step explanation:
We are given that a function
We have to find the discontinuity and zero of the given function.
Discontinuity: It is that point where the function is not defined.
It makes the function infinite.
When x=-4 then
It is indeterminate form
Function is not defined
After cancel out x+4 in numerator and denominator then we get
Substitute x=-4
Therefore, the point of discontinuity is (-4,-2).
Zero: The zero of the function is that number when substitute it in the given function then the function becomes zero.
When substitute x=-2
Then ,
The function is zero at (-2,0).
Hence, option C is true.