2 years ago

4r² - 2s³ for r = 1 and s = 5 Thanks!

Mathematics

2 answers:

Mila [183]2 years ago

3 0

4r^2=4 if r=1
2s^3=250 if s=5

Romashka [77]2 years ago

3 0

So we are given constants for this problem and looking at it, all we need to do is replace r & s with the numbers in the equation.

4(1)^2-2(5)^3 we will get -246

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How can we factorise the expression: 2x^6+17x^3+8?

LekaFEV [45]

Answer:

$(a + 2)( {a}^{2} - 2a + 4 )(2 {x}^{ 3} + 1)$

Step-by-step explanation:

$2x^6+17x^3+8 \\ = 2x^6+16x^3 + {x}^{3} +8 \\ = 2{x}^{3} ( {x}^{3} + 8) + 1( {x}^{3} + 8) \\ = ( {x}^{3} + 8)(2 {x}^{ 3} + 1) \\ = ( {x}^{3} + {2}^{3} )(2 {x}^{ 3} + 1) \\ = (a + 2)( {a}^{2} - 2a + {2}^{2} )(2 {x}^{ 3} + 1) \\ = (a + 2)( {a}^{2} - 2a + 4 )(2 {x}^{ 3} + 1) \\$