I dont know how to this but you probably make 4 3/8 and 2 1/2 into a decimal add all them together...
Answer:
(a) How many are there to select 2 pairs of gloves?
10 ways
(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)
130 ways
Step-by-step explanation:
We solve the above questions using Combination
Combination = C(n, r) = nCr
= n!/n! ×(n - r)!
(a) How many are there to select 2 pairs of gloves?
We have 5 pairs of gloves. Therefore, the number of ways to select 2 gloves =5C2
= 5!/2! × (5 - 2)!
= 5!/2! × 3!
= 5 × 4 × 3 × 2 × 1/(2 × 1) × (3 × 2 × 1)!
= 10 ways.
(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)
We are told to select 4 gloves out of the 10 gloves = 10C4
We have 5 pairs, we need to make sure that two out of the selected 4 make a pair = 5 × 2⁴
= 80
Hence,
10C4 - 5C4
= [10!/4! × (10 - 4)!] - 80
= 210 - 80
= 130 ways
I think there is no simplified fractions for this number it will be the same -4/17
Answer:
5
Step-by-step explanation:
The given equation is of the 5th order. Thus, we can expect 5 solutions/zeros.
First, fill in the variables with the numbers given so that
2b-3c
will then become
2(4)-3(2)
next, you refer to the order of operations to simplify the problem down, the multiplication being the first doable operations in this problem.
8-6
and next operation being subtraction.
2
is the final answer
