These tables of values represent continuous functions. For which functions will the y-values be the greatest for very large valu
es of x?
1 answer:
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Answer:
y = 130(24/13)^(x -10)
Step-by-step explanation:
The y-value changes by a factor of 240/130 = 24/13 for a unit change in the x-value. This means we can write the function as though it had an initial value of 130 and a growth factor of 24/13, translated 10 units to the right.
y = 130(24/13)^(x -10)
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<em>Additional comment</em>
This can also be written in the form ...
y = a·e^(kx)
where a=130·(24/13)^(-10) ≈ 0.28266, and k=ln(24/13) ≈ 0.61310
