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3 years ago

8, 20, 50, ... Find the 10th term.

Mathematics

1 answer:

Murljashka [212]3 years ago

3 0

Answer:

$a_{10}=\frac{5^{10}}{2^7} -1$

Step-by-step explanation:

$a_{n}=a_1 . r^{n}-1$

Here

$r=\frac{5}{2}$

$a_1 =8$

For n=10 (tenth Term)

$a_{10}=8(\frac{5}{2})^{10} -1$

$a_{10}=\frac{5^{10}}{2^7} -1$

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Answer:

Step-by-step explanation:

The equation will be in the form

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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4 years ago

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3 years ago

4x + 5y = 10

Vika [28.1K]

Answer:

For A = 32/5 and B = 8 the system of equations will have infinitely many solutions.

Step-by-step explanation:

Given equations are:

4x + 5y = 10

Ax + By = 16

The general form of linear equation in two variables is given by:

$ax+by = c$

Here a, b and c are constants and x,y are variables.

In the given equations, after comparing with the general form

$a_1 = 4\\b_1 = 5 \\c_1 = 10\\a_2 = A\\b_2 =B\\c_2 = 16$

"In order for a system of equations to have infinity many solutions,

$\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$ "

Putting the values we get

$\frac{4}{A} = \frac{5}{B} = \frac{10}{16}\\\frac{4}{A} = \frac{5}{B} = \frac{5}{8}\\Now\\\frac{4}{A} = \frac{5}{8}\\\frac{A}{4} = \frac{8}{5}\\A = \frac{8}{5} * 4\\A = \frac{32}{5}\\And\\\frac{5}{B} = \frac{5}{8}\\\frac{B}{5} = \frac{8}{5}\\B = 8$

Hence,

For A = 32/5 and B = 8 the system of equations will have infinitely many solutions.

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3 years ago