All categories

4 years ago

(8/5x² -2/3x³ +3/2x -1) - [ x/5x -3/2x² +2/3x +1/4]

Mathematics

1 answer:

tia_tia [17]4 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

What is the answer to x^2+4x+y^2

Alinara [238K]

Answer:

Step-by-step explanation:

6 0

3 years ago

Rebecca bought some snacks at the bulk food store. She scooped and

oee [108]

Answer:

1.85

Step-by-step explanation:

3 0

3 years ago

Use a tape diagram to relate the fraction 11/20 to a percent

Pavlova-9 [17]

The answer should be 55%

8 0

4 years ago

Solve the system of equations using the elimination method. 2x − 3y = 50;7x + 8y = −10

lorasvet [3.4K]

Answer: C. (10, -10)

Step-by-step explanation:

Given

1) 2x-3y=50

2) 7x+8y=-10

Multiply both sides of 1) equation by 3.5

1) 3.5(2x-3y)=3.5×50

7x-10.5y=175

2) 7x+8y=-10

Subtract 2) equation from the 1)

(7x-10.5y)-(7x+8y)=175-(-10)

-18.5y=185

y=-10

x=10

(10, -10)

Hope this helps!! :)

Please let me know if you have any questions

4 0

3 years ago

Read 2 more answers

In the figure below, \overline{AC} AC start overline, A, C, end overline and \overline{BE} BE start overline, B, E, end overline

mars1129 [50]

Answer:

$arc\ DBE=206^o$

Step-by-step explanation:

The picture of the question in the attached figure

<u><em>The question is</em></u>

Find the measure of arc DBE

step 1

Find the value of k

we know that

$m\angle EPC=90^o$ ----> by quarter of circle

$m\angle EPC=(33k-9)^o$

$(33k-9)^o=90^o$

solve for k

$33k=90+9\\33k=99\\k=3$

step 2

Find the measure of angle DPC

we know that

$m\angle DPC=(20k+4)^o$

substitute the value of k

$m\angle DPC=(20(3)+4)=64^o$

step 3

Find the measure of angle BPD

we know that

$m\angle BPD+m\angle DPC=90^o$ ---> by complementary angles

substitute the given value

$m\angle BPD+64^o=90^o$

$m\angle BPD=90^o-64^o=26^o$

step 4

Find the measure of arc DBE

we know that

$arc\ DBE=arc\ DB+arc\ BAE$

$arc\ DB=m\angle BPD=26^o$ ----> by central angle

$arc\ BAE=180^o$ ---> because a diameter divide the circle into two equal parts (BE is a diameter)

substitute

$arc\ DBE=26^o+180^o=206^o$

8 0

3 years ago

(8/5x² -2/3x³ +3/2x -1) - [ x/5x -3/2x² +2/3x +1/4]​

(8/5x² -2/3x³ +3/2x -1) - [ x/5x -3/2x² +2/3x +1/4]