Formula:
V = 1/3 * pi * r^2 * h
Plug in what we know:
V = 1/3 * 3.14 * 3^2 * 4
V = 37.68cm^3
So the volume is 37.68cm^3 which rounds to 37.7cm^3.
Answer:
yes there is a correlation
Step-by-step explanation:
here's how I found this by looking up all key words.
Answer:
7 (7/8)
Step-by-step explanation:
There
Answer:
a. Yes, it will float in oil since it is less dense than oil.
b. No, it won't float in oil since it is more dense than the oil itself.
c. Yes, it will float in water since, the water is more dense than the object itself.
x^2 + y^2 - 6x - 4y - 12 = 0
x^2 - 6x + y^2 - 4y = 12
x^2 - 6x + 9 + y^2 - 4y + 4 = 12 + 9 + 4
(x - 3)^2 + (y - 2)^2 = 25