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Katen [24]
3 years ago
10

Please help ASAP! I'll give Brainliest!

Mathematics
2 answers:
Maurinko [17]3 years ago
8 0

Answer:

g(x) =  3(3^x) - 2

Step-by-step explanation:

f(x) = 3^x  has a y intercept at x = 0 and when x = -1  y = -1/3. Now g(x)  passes through (-1,-1)  - the y-intercept is a stretch of 3  compared with f(x) so  we can write  3 f(x)  =  3(3^x) to allow for this. But  3(3^x)  passes though the point (0,3)

whereas the given graph pass though (0,1) so we need a translation down of - 2 to get the answer which gives

g(x) =  3(3^x) - 2

Murljashka [212]3 years ago
3 0

We have been given a graph of function g(x) which is a transformation of the function f(x)=3^x

Now we have to find the equation of g(x)

Usually transformation involves shifting or stretching so we can use the graph to identify the transformation.


First you should check the graph of f(x)=3^x

You will notice that it is always above x-axis (equation is x=0). Because x-axis acts as horizontal asymptote.

Now the given graph has asymptote at x=-2

which is just 2 unit down from the original asymptote x=0

so that means we need shift f(x), 2 unit down hence we get:

y=3^x


but that will disturb the y-intercept (0,1)

if we multiply 3^x by 3 again then the y-intercept will remain (0,1)

Hence final equation for g(x) will be:

g(x)=3(3^x)-2


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Choose all the functions that give the sequence:
TEA [102]

Hence, the functions that produce given sequence are:

f(n) = 2n + 1

f(n) = 2(n − 1) + 3

Further explanation:

We will put n=1,2,3,4,5 to find which functions give the given sequence

<u>f(n) = 2n − 1</u>

Putting values of n

f(1)=2(1)-1=2-1=1\\f(2)=2(2)-1=4-1=3\\f(3)=2(3)-1=6-1=5

This function doesn't generate the given sequence

<u>f(n) = 2n + 1</u>

Putting values of n

f(1)=2(1)+1=2+1=3\\f(2)=2(2)+1=4+1=5\\f(3)=2(3)+1=6+1=7\\f(4)=2(4)+1=8+1=9\\f(5)=2(5)+1=10+1=11

This function generates the given sequence.

<u>f(n) = 2(n − 1) − 3</u>

Putting values of n

f(1) = 2(1 -1) -3=2(0)-3=0-3=-3\\f(2) = 2(2 -1) -3=2(1)-3=2-3=-1\\f(3) = 2(3-1) -3=2(2)-3=4-3=1

This function doesn't generate the given sequence

<u>f(n) = 2(n − 1) + 3</u>

Putting values of n

f(1) = 2(1 - 1) + 3=2(0)+3=0+3=3\\f(2) = 2(2 - 1) + 3=2(1)+3=2+3=5\\f(3) = 2(3 - 1) + 3=2(2)+3=4+3=7\\f(4) = 2(4 - 1) + 3=2(3)+3=6+3=9

Hence, the functions that produce given sequence are:

f(n) = 2n + 1

f(n) = 2(n − 1) + 3

Keywords: Functions, Sequence

Learn more about functions at:

  • brainly.com/question/3071107
  • brainly.com/question/3126500

#LearnwithBrainly

8 0
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