Answer:
The required co-ordinate is (-2, -5).
Step-by-step explanation:
For a given point, reflection of a point (x, y) across a horizontal line y = k, the reflected co-ordinates will be: 
.
Here, (x, y) = (-2, 7) then reflection along the line y = 1, we get:
= (-2, -5)
The reflected point is (-2, -5).
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
6
Step-by-step explanation:
1. get rid of parentheses: 12x -6 = 10x +6
2. group like terns together: 12x-10x = 6+6
3. simplify: 2x = 12
4. divide both sides by 2: x=6
Which one is question 20??
