I'm going to assume that the room is a rectangle.
The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle.
You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:

Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.
The dimensions of your room are 25ft (length) by 24ft (width).
Answer: 
Step-by-step explanation:
R is the event of getting a red jelly bean. 22 out of the 150 jelly beans are red. That means it is a
chance of getting a red jelly bean.
Simplified that is 
Answer:
5 hours
Step-by-step explanation:
189-32=157
157/33 is about 4.76
4.76 rounded is 5 so the job took 5 hours
Answer:
a)
b) 
c) 
Step-by-step explanation:
Part a
The significance level given is
and the degrees of freedom are given by:

Since we are conducting a right tailed test we need to find a critical value on the t distirbution who accumulates 0.1 of the area in the right and we got:

Part b
The significance level given is
and the degrees of freedom are given by:

Since we are conducting a left tailed test we need to find a critical value on the t distirbution who accumulates 0.01 of the area in the left and we got:

Part c
The significance level given is
and
and the degrees of freedom are given by:

Since we are conducting a two tailed test we need to find a critical value on the t distirbution who accumulates 0.025 of the area on each tail and we got:

Answer:
-3/2
Step-by-step explanation:
We have to see where the point lies, check the x-axis from the graph.
(-3/2, 1/2)
x = -3/2