Angles ∠MOK and ∠NOL are identical by opposite angle theorem.
∠M = ∠N through given information
∠MKO and ∠NLO are congruent. Since the other two angles of each triangle are equivalent, the last angle must be equivalent to the last angle of the other triangle. (180 - ∠1 -∠2 = ∠3); you could also prove ∠MKO = ∠NLO by stating that the opposite sides of the two angles are congruent.
ΔMKO and ΔNLO by Angle-Angle-Side theorem
since ΔMKO and ΔNLO, all corresponding parts of both triangles are congruent, so therefore MO ≅ NO
Answer: 18x2 + 69x + 65
Step-by-step explanation:
(3x + 5) (~6x + 13)
1. 3x(6x + 13) + 5(6x + 13)
2. 18x2 + 39x + 5(6x + 13)
3. 18x2 + 39x + 30 + 65
4. 18x2 + 69 + 65
Answer:
-4 or -3
Step-by-step explanation:
Calculate the determinant:
D = b^2 - 4ac = 49 - 48 = 1
Apply the formula:
x = (-b +- sqrt(D))/2a = (-7 +- 1)/2 = -4 or -3
Answer:
C
Step-by-step explanation:
3/6 = 1/2
Answer is 0= -2
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