Without that value, we can't solve your problem, unless you are looking for an algebraic equation.
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
<u>(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)</u>
Step-by-step explanation:
Given :
Solving :
- (a + b)⁸
- <u>(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)</u>
[1] y = -x + 5
3x + 3•(-x +5) = 10
0 = -5 => NO solution
Alright, so 2x+2=0 (with x being the number) is what I'm getting from this. Subtract 2 from both sides to get 2x=-2, and then divide by 2 to get x=-1
