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Stolb23 [73]
3 years ago
6

A

Mathematics
2 answers:
Sergio039 [100]3 years ago
5 0

Answer:

$720

Step-by-step explanation:

The equation set up for this problem is 40x18 because for every one hour Mr. Thompson works, he earns $18.

kotykmax [81]3 years ago
4 0

Answer:

$720 in one week

Step-by-step explanation:

40 * 18

$720

Best of Luck!

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Coach Johnson needs to buy shin guards for the Junior Varsity and Varsity basketball
madreJ [45]

Answer:

Coach Johnson will save $1.50

Step-by-step explanation:

1. The first step is to calculate the unit price for each of the packages, ie. how much a single shin guard costs.

If we look at the package of 10 shin guards for $14.50, we can calculate the unit price by dividing the package price ($14.50) by the number of shin guards (10). Thus we get:

14.50/10 = $1.45

Now, if we do the same for the package of 15 shin guards for $22.50, we get:

22.50/15 = $1.50

2. Now we can see that the lowest unit price is $1.45 (package of 10 shin guards) and the highest unit price is $1.50 (package of 15 shin guards).

3. There are two ways to see how much he would save, so I will show both here.

1) First calculate how much the coach will have to pay for a pack of 30 shin guards for each of the packages:

3 packages of 10 shin guards for $14.50 = 3*14.5 = $43.50

2 packages of 15 shin guards for $22.50 = 2*22.5 = $45.00

Now subtract the second value from the first: 45-43.5 = 1.5

Therefor, he will save $1.50.

2) The second method is perhaps what I would personally use as it is a little quicker; so we already know that the unit price for the pack of 10 is $1.45 and the unit price for the pack of 15 is $1.50 - thus, we can say that there is a difference of $0.05 per shin guard in price. Now if we were going to calculate how much the coach would save in buying 30 shin guards, we could simply multiply how much he saves on a single shin guard by 30. Thus, we get:

0.05*30 = 1.5

Therefor, again we get the same answer that Coach Johnson would save $1.50.

Hope that helps :)

8 0
3 years ago
two pages that are back-to-back in this book have 203 as the sum of their pages.what are the page numbers?
butalik [34]
2 pages back to back.....x and x + 1

x + x + 1 = 203
2x + 1 = 203
2x = 203 - 1
2x = 202
x = 202/2
x = 101

x + 1 = 101 + 1 = 102

the 2 page numbers are : 101 and 102
5 0
3 years ago
2 ³✓3 × 3✓2 please answer this fast
Lady_Fox [76]

2\sqrt[3]{3} \cdot 3\sqrt 2\\\\=6 \cdot \sqrt[3]{3} \cdot \sqrt 2\\\\=6\cdot 3^{\tfrac 13} \cdot 2^{\tfrac 12}\\\\\approx 12.24

3 0
2 years ago
Read 2 more answers
which answer choice is it?
qwelly [4]

Answer:

A

Step-by-step explanation:

∠ AOC = 90° and

∠ AOB + ∠ BOC = ∠ AOC , that is

x + 8 + 2x = 90

3x + 8 = 90 ( subtract 8 from both sides )

3x = 82 ( divide both sides by 3 )

x = \frac{82}{3}

Then

∠ BOC = 2x = 2 × \frac{82}{3} = \frac{164}{3} ≈ 54.67° ( to 2 dec. places )

8 0
3 years ago
Reduce this algebraic fraction ab^2x/ab^2y=
Strike441 [17]

                             ab^2x
\<span>ab^2x/ab^2y  = --------------- = x/y.  the ab^2 factor cancels from numerator
                              ab^2y                 and denominator.

</span>
6 0
4 years ago
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