Answer:
20π sq ft ≈ 62.83 sq ft
Step-by-step explanation:
Area of table with diameter 8 ft = π*8^2/4 = 16π
Area of table with diameter 12 ft = π*12^2/4 = 36π
Difference between the area of the tables ;
= 36π - 16π
= 20π sq ft ≈ 62.83 sq ft ( π = 3.14)
All these appear to be physic phenomena because they do not change the composition of the matter.
<span>However, while rotations, translations and reflexions do not alter the volume of the matter, dilation does increase the volume. </span>
<span>Dilation, by definition, is an enlargement of the matter and directly opposed to contraction. For example, heat dilates the matter, while colds contract it. The exception to this is that when water becomes ice due to cold, it increases in volume.</span>
8x+1=-x-1 4-5x=1+6x
8x+x=-1-1 -5x-6x=1-4
9×=-2 -11×=-3
×=-2/9 ×=3/11
∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.
Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².
∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find
where 
is the length of the altitude originating from vertex O, and so
where 
is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².
So, the total area of the shaded region is
(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²
Answer: B. 95.0
Step-by-step explanation:
In statistics , the famous empirical rule says that " if the data is normally distributed then 68% of the observations will be contained within 
standard deviations from the arithmetic mean, 95% of the observations will be contained within 
standard deviations from the arithmetic mean and 99.7% of the observations will be contained within 
standard deviations from the arithmetic mean".
Hence, B is the correct answer.
