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sleet_krkn [62]

3 years ago

14

Nina earns $15 for each yard she mowes. she wants to buy a dress that coasts $109. how many yards will she need to mow to earn m

oney for the dress? explain

1 answer:

xxTIMURxx [149]3 years ago

8 0

she will need to mow 8 yards because 109 divided by 15 equals 7.2 but she cant just mow 7.2 yards so you round up to 8 yards

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Subtract. Your answer should be a polynomial in standard form. (-7d2 – 5d f3 – 3f3) - (8d+ 4d f3 +253)

lapo4ka [179]

Answer:

-9df^3 - 3f^3 - 7d^2 - 8d - 15625

Step-by-step explanation:

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3 years ago

What is<br> is 1/4 + 9/10y -3/5y +7/8 written in simplest form?

Leviafan [203]

Answer:

Step-by-step explanation:

$\frac{1}{4}+\frac{9}{10}y - \frac{3}{5}y+\frac{7}{8}\\\\=\frac{1}{4}+\frac{7}{8}+\frac{9}{10}y-\frac{3}{5}y\\\\$

Combine like terms. 1/4 and 7/8 are like terms and LCD of 4 and 8 is 8

9/10y and -3/5y are like terms and LCD of 10 , 5 is 10

$= \frac{1*2}{4*2}+\frac{7}{8}+\frac{9}{10}y-\frac{3*2}{5*2}y\\\\=\frac{2}{8}+\frac{7}{8}+\frac{9}{10}y-\frac{6}{10}y\\\\=\frac{9}{8}+\frac{3}{10}y$

5 0

3 years ago

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The average height of women between ages 30-39 is 163.2 cm with a standard deviation of 9.3 cm. Find the probability that a woma

Darina [25.2K]

Answer:

D) 0.6346

Step-by-step explanation:

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3 years ago

In a survey of adults aged 57 through 85 years, it was found that 86.6% of them used at least one prescription medication. Com

OleMash [197]

Answer:

a) 272 used at least one prescription medication.

b) The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

Step-by-step explanation:

Question a:

86.6% out of 3149, so:

0.866*3149 = 2727.

272 used at least one prescription medication.

Question b:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 3149, \pi = 0.866$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 - 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.856$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 + 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.876$

For the percentage:

0.856*100% = 85.6%

0.876*100% = 87.6%.

The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

7 0

3 years ago

In the given right triangle, find the missing length to the nearest tenth.

Jlenok [28]

Answer:

D. 25 ft.

Step-by-step explanation:

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3 years ago

Read 2 more answers