Step-by-step explanation:
Q1 . (f+g)(x) = f(x) + g(x)
=4x-4 +2x^2 -3x
= 2x^2 + x -4
Q2. (f-g)(x) = f(x) - g(x)
= 2x^2−2 - (4x+1)
= 2x^2 -2 -4x -1
= 2x^2 - 4x -3
Q3. h(x)=3x−3 and g(x)=x^2+3
(h.g)(x) = h(x) × g(x)
= (3x-3) × (x^2 + 3)
=3x^3 -3x^2 + 9x -9
Q4.f(x)=x+4 and g(x)=x+6
(f/g)(x) = f(x) ÷ g(x)
= x+4 / x+6
the domain restriction is x>-6
x<-6
x doesn't equal (-6)
Answer:-1
Step-by-step explanation:
I rewrote it so it looks like this:
6y+6(1+3y)=-18
6y+6(1)+6(3y)=-18
6y+6+18y=-18
24y+6=-18
<u> -6 -6</u>
<u>24y</u>=<u>-24</u>
24 24
y=-1
Answer:
x^5y^5
Step-by-step explanation:
<em>here's</em><em> your</em><em> solution</em>
=> if base are same then power get added in multiplication
=> so, x^2 * y^4 * x^3 * y^1
=> x^2 * x^3 * y^4 * y^1
=> x^5*y^5
hope it helps
The answer should be 101.
